Knitel's InfinityPump

[hartiberlin]

Okay, Tom,
now I see, what you mean, if we compare it with a syringe,
sucking up water,
we have to calculate in the diameter ratios of the "syringe rod" versus the needle diameter,
so in our example
the ratios of the diameter of the main big cylinder versus the right 1 cm diameter tube.

So the pressure ratios are behaving like a lever ratio,
where the
diameter tube 1 / diameter tube 2 = watermass1 / watermass 2

So if we have watermass 1 = 15.7 Kg  and diameter tube 1 = 1 cm
and diameter of tube 2= 100 cm we get for watermass 2= 1570 Kg.

Okay, so we need more than 1570 Kg to suck the 15.7 Kg in the small
tube up.

Now the question is, if we make the weight 2000 kg,
if we can make it in such a volume, that it will
still have a boyuant force up, when it is at the bottom
of the main cylinder and valve V3 opens ?

[tbird]

Sorry, I meant the tube to have a 1 cm diameter.

So the height of 5Meter will have 15.7 kg of water in it.
As the air pressure is pressing on the water surface,
it is just as a syringe, which needs to pull 15.7 Liters of water up 5 Meters
high.
So you need to overcome 15.7 Kg of weight....

Tom do you mean, the dimensions of the 100 kg swimmer body play any role
in it ?  because the 1 cm diameter pipe is changed into a bigger cylinder
at the top at the V1 valve ?

Okay, than make the swimmer weight body 2000 Kg, where is the problem ?

hi stefan,

the tube can not have that much weight in it.  volume of a cylinder is pie (3.14) times radius squared (1cm) times height (500cm).  so we have 3.14 x 1 x 500 = 1570 cm3  1 cm3 of water weights 1 gram so we have 1570 grams.  isn't that 1.57 kg?

air pressure has no place in these calcs, except to the degree the valve (like your thumb over the end of a straw) at the top prevents the water from flexing its weight and falling back into the supply.  let's not get distracted yet.

i see you just posted again.  i'll pass this along and then address the other.

tom

[xnonix]

Someone wants to make the model in this software? Its free lincensing. As I am computer engineer I need to see the system working to believe it.

http://www.filebuzz.com/fileinfo/17608/20sim_Viewer.html

xnonix

[tbird]

Okay, Tom,
now I see, what you mean, if we compare it with a syringe,
sucking up water,
we have to calculate in the diameter ratios of the "syringe rod" versus the needle diameter,
so in our example
the ratios of the diameter of the main big cylinder versus the right 1 cm diameter tube.

So the pressure ratios are behaving like a lever ratio,
where the
diameter tube 1 / diameter tube 2 = watermass1 / watermass 2

So if we have watermass 1 = 15.7 Kg  and diameter tube 1 = 1 cm
and diameter of tube 2= 100 cm we get for watermass 2= 1570 Kg.

Okay, so we need more than 1570 Kg to suck the 15.7 Kg in the small
tube up.

Now the question is, if we make the weight 2000 kg,
if we can make it in such a volume, that it will
still have a boyuant force up, when it is at the bottom
of the main cylinder and valve V3 opens ?

hi stefan,

not sure if what you said is true here, but if we get to the same place for the same basic reason, good!

the volume to make it float is where the problem lies.  by the time it is big enough, there is no more room to travel.

in your other post, you asked about shape.  can you now see it has to increase to DISPLACE more water weight than it weights itself?  it doesn't matter if it is long and skinny or short and fat.  it still needs to DISPLACE 2000 kg (last size suggested) of water.  how big is that?  how much water is that?

are we getting a handle now?

tom

[sushimoto]

Someone wants to make the model in this software? Its free lincensing. As I am computer engineer I need to see the system working to believe it.

http://www.filebuzz.com/fileinfo/17608/20sim_Viewer.html

xnonix

It is restrictet.
You can not save your work in the freeware-version.