Coral Castle 50 year old secret - NOW here REVELED

[Koen1]

I read what you wrote yet I still don't really follow... sorry

Perhaps someone who does get the point could rephrase
this so that it becomes more understandable?

[BAHammer]

I read what you wrote yet I still don't really follow... sorry

Perhaps someone who does get the point could rephrase
this so that it becomes more understandable?

  Koen,
About the only way having a 60 meter pipe would matter would be the compressive forces the water would be under. It would be equivalent to about 6 atmospheres.
This is what makes me think a part of the design has to do with transferring thermal energy.
Any time a fluid is compressed, it gives off heat. Just check your refrigerator. The refrigerant is placed under pressure and gives off a lot of heat. Then when it goes into a vacuum chamber, it absorbs heat.
I think this system might be something similar in principle.

                                                                                 Jim     

[alan]

with all respect, hammuraby, install firefox and with it install spellingchecker (really works great), it is very unreadable what you're typing.
Leedskalnin is an interesting subject.

[hammuraby]

excuse me for my english, one more time.....
i had read about heat, or about electricity, and air compressed
NOT at ALL, forghet it , for now ...,
that is not necessaire, here is just meccanical sistem
for now !!......and,when the meccanic sistem will be understand, other will came....the best will came!! step by step

FIRST DATA you have to evalue the tube that came from the pool to the underground level showed in the #1 picture after the fhoto:
that in the semple is 15 cm of diameter,
176 cm2 X 60.00 mt of delevell from surface pool to undergraund water level,
is about 1020 Kg = 10 000N
that PULL on the pump ex: left

(@BAHammer...you can see as you wont, 6atm =6kg/cm2 x 172cm2 = 1020kg x 9.8 = c.a.10 000 N !!)

when you need to UP a WEIGHT, you have to reduce the Nm that result on/at gear-box,
less then this levell (10 000Nm); exemple in diseig 4000 kg , need gear 4:1 ( 9 900Nm ex: on right of pomp)
the resistence (loud) is less then the water power (heavyness of water column);
10 000Nm win on 9 900

and, what s happen?: <-------:

the pull from water win and the water go DOWN the tube (from the pool) and then the loud go UP

then, when you need to put down the WEIGHT you will use a gear 40:11
and the heavyness from the LOUD, put on the pump  10 100 Nm in the other side (ex: right side).
this drags a water flow (and the pump versus) to reverse versus, -------->
because 10 100 Nm win on 10 000 still Nm traction from the 60 mt long water tube.
the loud go DOWN, and the water is pomping UP

IT WORK as a BALANCE,
charge weight up ------>short gear----> discharge water down to bottom of sink
charge water up to pool ------>long gear----->  discharge weight down

easly, and notthing else  (for now!)

and the SECRET is find a point in perfect balance on conic-gear ,
then, a little short go loud go UP, a little long loud do DOWM
at the same time water go DOWN, or water go UP !! really easy a lot !!

whit this sistem, you can SAVE close that all the energy-water used befoure....
called also "discharge energy recicled"
(naturally, if the hi ness of stat point and end point is on the same level)
total power also emprove by rain ....

VERY IMPORTANT:
is that the two mouths of the tube can not breath air , one on water subterrain, and other in waterpool

[BAHammer]

excuse me for my english, one more time.....
i had read about heat, or about electricity, and air compressed
NOT at ALL, forghet it , for now ...,
that is not necessaire, here is just meccanical sistem
for now !!......and,when the meccanic sistem will be understand, other will came....the best will came!! step by step

FIRST DATA you have to evalue the tube that came from the pool to the underground level showed in the #1 picture after the fhoto:
that in the semple is 15 cm of diameter,
176 cm2 X 60.00 mt of delevell from surface pool to undergraund water level,
is about 1020 Kg = 10 000N
that PULL on the pump ex: left

(@BAHammer...you can see as you wont, 6atm =6kg/cm2 x 172cm2 = 1020kg x 9.8 = c.a.10 000 N !!)

when you need to UP a WEIGHT, you have to reduce the Nm that result on/at gear-box,
less then this levell (10 000Nm); exemple in diseig 4000 kg , need gear 4:1 ( 9 900Nm ex: on right of pomp)
the resistence (loud) is less then the water power (heavyness of water column);
10 000Nm win on 9 900

and, what s happen?: <-------:

the pull from water win and the water go DOWN the tube (from the pool) and then the loud go UP

then, when you need to put down the WEIGHT you will use a gear 40:11
and the heavyness from the LOUD, put on the pump  10 100 Nm in the other side (ex: right side).
this drags a water flow (and the pump versus) to reverse versus, -------->
because 10 100 Nm win on 10 000 still Nm traction from the 60 mt long water tube.
the loud go DOWN, and the water is pomping UP

IT WORK as a BALANCE,
charge weight up ------>short gear----> discharge water down to bottom of sink
charge water up to pool ------>long gear----->  discharge weight down

easly, and notthing else  (for now!)

and the SECRET is find a point in perfect balance on conic-gear ,
then, a little short go loud go UP, a little long loud do DOWM
at the same time water go DOWN, or water go UP !! really easy a lot !!

whit this sistem, you can SAVE close that all the energy-water used befoure....
called also "discharge energy recicled"
(naturally, if the hi ness of stat point and end point is on the same level)
total power also emprove by rain ....

VERY IMPORTANT:
is that the two mouths of the tube can not breath air , one on water subterrain, and other in waterpool

  hammuraby ,
  There are 2 things that could help this work.
The first is to use a multiple set of blades for the water to flow over on it's way down. And the second is to have room under the blades for the water to fall.
This might allow you to have a sufficient static head to push water up the other side. This would require less suction of the up pump.
Other wise, heated water under a vacuum might require less energy to draw a suction on.

                                                                                           Jim