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Overunity Machines Forum



Sjack Abeling Gravity Wheel and the Worlds first Weight Power Plant

Started by AquariuZ, April 03, 2009, 01:17:07 PM

Previous topic - Next topic

0 Members and 57 Guests are viewing this topic.

hansvonlieven

Bessler's wheel was 12 feet in diameter. That means at 50 RPM it took well over a half a second for the weight to travel the distance. How do you think that compares to a weight dropped 12 feet?

Hans von Lieven

Edit: Acceleration due to gravity is 9.81 m/s2 near the surface of the earth
When all is said and done, more is said than done.     Groucho Marx

i_ron

Quote from: hansvonlieven on May 11, 2009, 06:47:48 PM
G'day Ron,

You cannot ever reach free fall speed if the weight is attached to a wheel because of the forced trajectory and the longer path. The terminal velocity, assuming only gravity as propulsive force, is actually quite low.

Hans von Lieven

Correct, that is why I said,"as close to", to emphasize that if
one gently lowers the weigh on a pillow 2 or 3 inches it will
not gain any weight. You know this but for the others what
I was attempting to imply was suppose you were standing on a 100 foot building and you had your assistant throw a 10 lb
weight on a ten foot rope over the parapet ... you could if well
braced stop it. Now repeat the experiment with a 50 foot rope

A different outcome for sure!

Edit:
(I was coming on to this from my pendulum experience where
a 20 Kg bob swinging 120 degrees will lose say 10 Kg's at its upstroke and gain 10 Kg's (weigh 30Kg's) at the 6:00 down stroke. I don't see this being modeled in the sims...)

So all I was saying, the greater the diameter and the greater the rim speed the greater chance this might work.

Ron
 

hansvonlieven

That would all be very nice if you didn't have to bring the weight up again. The higher the drop the higher the lift to get to the starting position. It is always even stephens minus losses, whichever way you twist or turn it.

Hans von Lieven
When all is said and done, more is said than done.     Groucho Marx

i_ron

Quote from: hansvonlieven on May 11, 2009, 07:50:09 PM
That would all be very nice if you didn't have to bring the weight up again. The higher the drop the higher the lift to get to the starting position. It is always even stephens minus losses, whichever way you twist or turn it.

Hans von Lieven

G'day Hans,

All to true, but if one looks at this from a pendulum perspective then 10 kg dropped from 2:00 will weigh 15kg
at 6:00 and ride all the way up the ramp to 9:00 where it will weigh zero Kg, just before it changes direction and falls back down.

I was not advocating that this would work... only pointing
out the fallacy of static frame testing which fails to discern
the weight changes that a dynamic model undergoes...

Onyaz,

Ron

PS: near free fall speed is not that hard to achieve... a
pendulum does it automatically. I know how you love pendulums... so here is one of mine...

http://www.youtube.com/watch?v=iI_ooL8hcrE



LarryC

Quote from: hansvonlieven on May 11, 2009, 06:47:48 PM
G'day Ron,

You cannot ever reach free fall speed if the weight is attached to a wheel because of the forced trajectory and the longer path. The terminal velocity, assuming only gravity as propulsive force, is actually quite low.

Hans von Lieven

Ah, this brings up an interesting question for you learned gentlemen.

Taking into account Hans statement and since we all know that ignoring air resistance, an object will increase its velocity by 9.8m for each second of fall. So lets say that a gravity machine has an acceleration of 5 m/s2 on the fall and no loss on the lift. Would not the same velocity increase occur for a working gravity machine for each rotation?

Regards, Larry