Claimed OU circuit of Rosemary Ainslie

[MileHigh]

Ramset:

And then a claim like this? ,From a Big ass lab!!

The scrutiny would have been meticulous !!

SOMETHING IS REALLY SCREWY HERE!!

Exactly.  If this effect was real and was observed it would have become world wide news eight years ago.

I will quote the line that that comes from the laws of thermodynamics that the believers hate, "It's impossible."

On a simple practical level this circuit is nothing more than a coil in series with a resistor in series with a diode.  Somebody connects two wires of a battery to start a current flow through the coil and the resistor.  Then they remove the wires and the coil discharges through the resistor and the diode.

That is all there is.

And when I was 12 years old, my father took me to a circus, the greatest show on earth.
There were clowns and elephants and dancing bears.
And a beautiful lady in pink tights flew high above our heads.
And so I sat there watching the marvelous spectacle.
I had the feeling that something was missing.
I don't know what, but when it was over,
I said to myself, "Is that all there is to a circus?"

Is that all there is, is that all there is?
If that's all there is my friends, then let's keep dancing.
Let's break out the booze and have a ball.
If that's all there is...

Welcome to the Rosemary and Aaron circus.

There is no shortage of clowns.

MileHigh

[poynt99]

One scope shot of RA circuit without the flyback diode (now the accepted version?)

Note no avalanche possible based on this simulation. Peak Drain voltage is only about 88V, and that is from Drain to GND. It will be a few volts less from Drain to Source.

Main purpose of this scope shot is to clearly show (by conventional analysis) that the ringdown current present in the supply battery or source is AC, meaning that it's net average current measured inside the battery is zero. Notice the red trace "0A" and the oscillatory wave form equally above and below the zero line as the current rings down.

.99

[poynt99]

Thanks FT. Good docs

.99

[MileHigh]

.99:

Thanks again for your efforts.  Some interesting colour commentary:  This graph clearly demonstrates the relationship between the voltage and the current in an inductor.

v = L di/dt  (the voltage across an inductor is proportional to the rate of change of current with respect to time)

It's very clear starting at 849 nSec where the exponential drop in current causes an exponential rise in voltage.  The first derivative with respect to time of exp^(t) is exp^(t).

Note that "exp" is the base of the natural logarithm = 2.7182818.... (on to infinity)

Then when the oscillation starts you can clearly see that they are 90 degrees out of phase.  The first derivative with respect to time of sin(t) is cos(t).  (which is equal to sin(t + 90 degrees))

I am simplifying things and forgetting the shunt resistor and probably have some polarities wrong but the key point is to try to understand what v = L di/dt means.  Your graph plots current as a function of time, i(t), and voltage as a function of time v(t).

Hence.... <drum roll>......

v(t) = L di(t)/dt.

You just drop in the equation for i(t) and then calculate the first derivative of that equation with respect to time which gives you a new equation that's also a function of time.  Them multiply the new equation by the value of the inductance to get a new equation for v(t).

The first derivative of i(t) with respect to time is just the slope of the i(t) plot.  You can easily eyeball the slope of the i(t) plot and see how that generates the v(t) plot.

Great job!

MileHigh

Aaron:  Care to comment?  Is this in the realm of your experience?  (ha ha - just rubbing it in to illustrate how ridiculous your comments were about me not knowing what I was talking about.  Stick with "compressed time potential" and using your tongue or try to really understand what is going on, your choice)

[TinselKoala]

MH, you seem to forget: While you and I and .99 and Hoppy and Henieck and lots of others of us were sweating through those years of Calculus classes, solving stacks of problems nightly, sitting weekly quizzes and monthly exams, Rosemary--and probably Aaron, from the sounds of it--were pursuing less "relevant" educational pathways. Until last week Rosemary thought "integration" was somehow opposite to "apartheid", and no doubt Aaron still believes that derivatives are bought and sold in financial markets.