Selfrunning Free Energy devices up to 5 KW from Tariel Kapanadze

[Zeitmaschine]

The diagram that you posted is showing an input of almost an amp, even without a load.

That almost one amp creates the heat in the device (heating of the inverter and the transformer). So we have 0.9 amp input and heat output to the amount of that 0.9 amp in idle condition.

In sparking condition the spark is the surplus (Over Unity) of heat (and light) output.

Otherwise that sparking would mean cooling of the transformer, so the spark takes heating away from the transformer to create itself with that energy. But I've never heard about a transformer running cooler with a sparking secondary coil than without.

That means something here is not in accordance with the textbooks. That's for sure.

Therefore the question is, how to get more energy from that spark? Something should be in resonance with some other thing. But I still don't know what.

[dllabarre]

Therefore the question is, how to get more energy from that spark? Something should be in resonance with some other thing. But I still don't know what.

What I've been working on is fine tuning a Kapanadze type device where every freq is a harmonic of MAINS either 50/60hz that matches the input freq of your country.
DonL

[Khwartz]

Since the spark dissipates energy in form of light and heat, and since that energy is obviously not taken from the battery, then that energy has to come from some other place, namely the environment.

When the one side of the spark gap (during each 50Hz cycle) is positive (lack of electrons) then it attracts electrons from ground electrostatically on the other side. But because of the spark gap there is a spark which dissipates that energy instantaneously. When there is no spark (direct connection) then there is nothing that can make use of that energy. Then it's like a battery connected to nothing. Without sparking a voltmeter shows a few hundred volts across the spark gap. Most likely that reading is too low because of the internal resistance of the voltmeter which is not infinite.

Correct me if I'm wrong: In an ordinary electric circuit there can't be current without dissuipation of energy at the same time. You can't have current in an electric circuit without the dissipation of light or heat or magnetic waves etc. That means, if there is nothing in the ground connection that dissipates (converts) the energy (makes use of the energy in some way like a spark) then the energy is there (like in a battery without a connected load) but it can't be measured.

How to measure the voltage of a battery without creating a closed circuit (putting load on the battery) through a measuring instrument?

Dear Zeitmaschine, thanks for your detailed reply in explanations of your viewpoint.

Correct me if I am mistaking but if I understand well, what you mean is that the consumption of the power supply system looks not varying with or without sparks, right?

What if the output of the spark gap (heat + light) is so weak it is not measurable by what ever you use to know the consumption in input?

What about to set a insultated black box around the spark gap and graph the increase of temperature respect to the time, so that we will know exactly the power output of it?

What about probes to know the voltage at input and linear résistance to know the current. Anyway, if setup is same before and after closing the vircuit with the spark gap, we don't really care is the instruments you use are not perfect, the imperfection is same in the two cases and it is the comparison which is relevant.

Regards.

[Zeitmaschine]

What if the output of the spark gap (heat + light) is so weak it is not measurable by what ever you use to know the consumption in input?

Even then it contradicts the textbooks. The textbooks saying an electric circuit must be closed otherwise no current can flow. But here a current flows clearly without a closed circuit.

Shorting the transformer's HV coil through a 10MOhm (!) resistor draws immediately around 60mA of additional current from the battery.

Now an interesting thing happens when the HV coil is shorted via that 10MOhm resistor and the spark fires to ground at the same time: The measured DC current goes down. Not much, just a few mA. But I think this is proof that the ground spark adds energy to the circuit, not drawing energy from it.

And that shorting reminds me somehow of the Barbosa patent which says something about a shorted coil connected to ground in order to capture the electrons.

Thus instead of doing a lot of measurements -which can be correct or not- wouldn't it be simpler trying to get more additional energy from the environment so that the circuit can self-run?

[dllabarre]

Even then it contradicts the textbooks. The textbooks saying an electric circuit must be closed otherwise no current can flow. But here a current flows clearly without a closed circuit.

It is a closed circuit.  The energy goes from the ground, thru SG, thru 1/2 coil, to the antenna in the air and the air is touching the ground 
The batt/inverter/other 1/2 of coil is just the exciter to get the energy flowing from the ground.
It's a theory....
DonL