Burn water for heating system

[kamax]

Hi,

After watching a video of Dr stiffler who use his SEC with electrodes into water to burn it, i'm asking myself if it can be a heating system.

Here is the video:http://www.youtube.com/watch?v=aanRgpfv144&feature=related

Of course only the flame don't produce a lot of heat but maybe with a metal plate on his top or something like this able to dispatch the heat into a room.
It don't use a lot of power to do this, so maybe it can be a good and cheap way.

But i don't have any SEC now, the tuning of his device seems hard to replicate. Maybe with another simple device we can produce the same effect.(joule thief and his pulsed dc/ac ?)

Any suggestion/help ?

[kamax]

Here is the video N°1 of his experiment: http://www.youtube.com/watch?v=lsX-j53_FDg&feature=related

He show that he need only 22.8V an less that 10ma (~0,03watt ?).

With the flame we can run a stirling motor(no?) and make the device self running in the same time it warm up a piece metal.

Isn't it interesting ? 

[Cloxxki]

Very nice, and such a low consumption, the battery might last longer than anyone cares to personally wait for to die?
As the bubbles don't "bang" when lit (in Dutch, HHO is know as the direct translation of bang gas), perhaps the flame may not be producing crazy heat like HHO flames are often demonstrated to do? Would be great to learn more about that flame. But already, I'd love to be able to buy such a setup, as an alternative to a candle. Candles are for sissies.

[Mark69]

Hi Kamax, yes, sounds like a good idea, use flame to run sterling motor which turns a small generator to produce electricity.  Give it a shot.

Mark

[WilbyInebriated]

hi kamax.
you could just go directly to electricity. like this:
http://www.youtube.com/watch?v=0_GqE5aDR68

remove the led and loop it back to the input of the SEC.
i am currently experimenting with something along these lines with a 15-3.

edit:
there is the JTEC also. the user lumen? has mentioned it a couple times IIRC.
http://www.johnsonems.com/?q=node/2