Understanding electricity in the TPU.

[sparks]

  There are endless sceanarios SM did not address.  How many batteries could you place in the television set. Will the tpu work inside a faraday cage.  Why is there no oscilliscope anywhere around there.  Are the bulbs really hot.  On and on.  You get to the point where the fascination with the specific device becomes counterproductive.  SM produced the tapes for one reason or another.  They have served their purpose.  Lets move on . 
   Towards this end.  If we take a capacitor and charge it from a dc scource.  Disassemble the capacitor and take the plate in hand and move it about the room past various metals can we charge the other metals via our movement.  A wonderful thing occurs inside a capacitor as it is being charged.  The force used to charge the plates results in the plates inside the capacitor to exert a pressure on the intervening dielectric.  This pressure was experienced by Tesla using pulsed dc at highfrequency.  This pressure is a vector field.  This pressure is 450psi in a typical thin film capacitor.
As you decrease the distance between the two metals of opposite charge the pressure rises expotentially with distance.  It approaches infinity as the gap is closed.  If you were in between two large walls of aluminum on casters as somebody charged this mega capacitor you would be crushed.  This force arising has nothing to do with input work.  We are charging a capacitor.  We know that we are able to stop charging the capacitor and days latter retrieve our action.  As we discharge the capacitor we find that the pressure between the two moveable walls is relaxed.  The moving walls represented a conductor moving.  When this conductor moves if it moves perpendicular to magnetic field lines it creates an emf.  So the simple act of charging a capacitor can result in bonus energy as the capacitor plates move like the copper wires move in a generator.

[forest]

sparks

I do not understand where is that pressure when you remove plates from charged capacitor.I can imagine that plates are like a squash walls between them there is a banging action of energy inside dielectric, but as one MIT video prove energy is stored in dielectric and you can change plates (moving dielectric to the other capacitor plates) and still have energy stored. Maybe it is that : this energy is stored in dielectric NOT in ELECTRONS but when metal plate is near it CREATE EQUIVALENT or electrons (or simpler : THE CHARGE)  inside plates. When plates are shorted current occur.

[sparks]

      Current precedes movement of charge carriers.  Charge carriers have mass while the force exerted by the electrical field does not.  Current is always flowing between points in space that have unequal amounts of charge.   When charged mass carriers move along with this current we get mass in motion.  Conductors are donars of relatively large amounts of charged mass that is free to move along with the electrical currents flowing in an electric field.  In a vacuum tube we have a cathode and anode seperated by a very good dielectric.  The problem being we insert  electrons to be accelerated from the scource of the cold current.  As the electron to be accelerated leaves the body of the cathode it leaves it less charged and reduces the accelerating force of the current flowing between the seperated charged mass.  This increases the amount of energy supplied from the scource to restablish the anode to cathode potential.  This is great if you wish to pull currents through a transformer controlled by the state of charge produced on the grid but it is not good for accelerating mass.

[EMdevices]

Current precedes movement of charge carriers.

if that were true we would already be living in a free energy society.  where is all this BS coming from?

Also, a capacitor that moves it's plates inward is expending energy, and it's true the charge stays the same, but the voltage potential has now dropped.  There is no free lunch here either.  Here's why.

V = E*d, where 'd' is the separation between the plates of a parallel plate capacitor.  The electric field 'E' stays the same (between the plates, not the fringes) so since 'd' is reducing, this implies 'V' is reducing.   Energy in a capacitor is U = 0.5 C V^2,   so reducing the voltage in half, reduces the energy by 1/4.

Forest, remember that point, that the "Charge" is NOT the electrons.

This basic truth is hard for many to accept, as this is not what most
EE's are taught. Full understanding of this allows the start of figuring
out just how current (Electron Flow...) is related to "Charge Flow"...

this was figured out many years ago and they teach this in physics101, if an electrical engineer missed this point i would be very worried and concerned, he's probably one of those that gravitated towards computer science and programing anyway, and I've known a few. 

1 electron =  âˆ'1.602×10âˆ'19 coulombs

[forest]

EMDevices


Topic is not that easy. While electron is a particle inside a wire there are energy levels it can has only so it's rather a smeared wave inside wire forming stationary "nodal points" we call electrons.