STEORN DEMO LIVE & STREAM in Dublin, December 15th, 10 AM

[freeorbo]

Am I right or wrong with this  ?
http://www.youtube.com/user/Larskro#p/a/u/0/_EapgzWFAh4

Larskro! Good to see you man! Love your videos.

[freeorbo]

It is YOU who inputs 0.124W, not the enviroment or something else.
rgds, Gyula

He's not consuming 0.124W.

Here's a question: If I connect a multimeter to either end of a battery, and it says 1.5V and 1 amp, am I consuming 1.5 watts?

What if I put between the battery and the multimeter an air coil of 1000 ft of wire and the meter now reads 1.5V and .98 amp. How much energy am I consuming then? My measurement is now 1.47 watts. am I consuming 1.47 watts? Or am I consuming the .03 watts lost to heat?

I would say the latter but I might be wrong.

[gyulasun]

Hi Freeorbo,

He's not consuming 0.124W. 

Why not?  Watch his video,  at 0:15 Larskro shows his digital multimeter, 31.2mA input current on display and then watch his power supply's meters at 0:28 show 4V DC input voltage and nearly 30mA current on his analog current meter, ok? 

If he did not take any current from his power supply i.e. there were zero current, his motor would stop. Agree with this? 
His power supply runs his motor.  And if you take out any current from a power supply or a battery at a certain voltage level, then you consume power from that source,  right? If you have a load like a bulb, it will load your battery continuosly, current hence power will be consumed in any moment of time, and if you run a pulse motor like Larskro, then current hence power will also be consumed but in an interrupted way and duty cycle comes into the consideration of the real power consumption.  BUT power is STILL consumed from the battery or the power supply, ok? It is just shown by Larskro's analog and digital meters.
Don't you agree?  Please answer.

Here's a question: If I connect a multimeter to either end of a battery, and it says 1.5V and 1 amp, am I consuming 1.5 watts?

If you properly measure the 1 Amper current that goes into a load and the battery still maintains its 1.5V output voltage, then YES you consume 1.5 W power from your battery.

What if I put between the battery and the multimeter an air coil of 1000 ft of wire and the meter now reads 1.5V and .98 amp. How much energy am I consuming then? My measurement is now 1.47 watts. am I consuming 1.47 watts? Or am I consuming the .03 watts lost to heat?

Yes you consume  1.47 W power  (not energy!) I agree with your number.
However, I do not understand why you think the loss is .03W only? 
Why do you relate your previous example of the 1.5W power consumption to this 1.47W power consumption? 
AGAIN: if you do not feed 1.5W (or whatever W) into your load, your load (in this case Larskro's motor) will not do its task, the motor will stop (or will not start at all without its needed input current.

rgds,  Gyula

[freeorbo]

Hi Freeorbo,
 

Why not?   his video,  at 0:15 Larskro shows his  multimeter, 31.2mA input current on display and then watch his power supply's meters at 0:28 show 4V DC input voltage and nearly 30mA current on his analog current meter, ok? 

If he did not take any current from his power supply i.e. there were zero current, his  would stop. Agree with this? 
His power supply runs his motor.  And if you take out any current from a power supply or a battery at a certain voltage level, then you consume power from that source,  right? If you have a load like a bulb, it will load your battery continuosly, current hence power will be consumed in any moment of time, and if you run a pulse motor like Larskro, then current hence power will also be consumed but in an interrupted way and duty cycle comes into the consideration of the real power consumption.  BUT power is STILL consumed from the battery or the power supply, ok? It is just shown by Larskro's analog and digital meters.
Don't you agree?  Please answer.

If you properly measure the 1 Amper current that goes into a load and the battery still maintains its 1.5V output voltage, then  you consume 1.5 W power from your battery.

Yes you consume  1.47 W power  (not !) I agree with your number.
However, I do not understand why you think the loss is .03W only? 
Why do you relate your previous example of the 1.5W power consumption to this 1.47W power consumption? 
AGAIN: if you do not  1.5W (or whatever W) into your load, your load (in this case Larskro's motor) will not do its task, the motor will stop (or will not start at all without its needed input current.

rgds,  Gyula

There's a difference between the amount of current flowing through a system and the amount of load or consumption. When you take a reading on a circuit that's just your meter and your battery, you're not consuming anything, you're just measuring the flow past the multimeter. The electrons go right back into the battery. They aren't "used up."

An Orbo motor has no load. That is the key fundamental issue at hand here. The circuit has no load. It performs no work. All of your input current returns back to the battery except for the miniscule amount of energy lost due to inductive heating. Basically some drop off during the trip. But none of the energy is converted into work or any other form of energy.

The work is done by the realigning magnetic domains in the toroidal cores, which is a permanent, renewable energy source that will never run out.

The reason that you see any change in current is because at lower RPMS the inductive gain caused by the magnetic interaction with the windings is lessened. It's not because that extra current is performing any work. It's because the system is less efficient at lower RPMS.


That's why we say the way to measure the performance of an Orbo system is to compare the losses in the coils to the work being performed. Standing current has no impact on the system because 99% or more of it is returned back to the battery.

[Omnibus]

An Orbo motor has no load. That is the key fundamental issue at hand here. The circuit has no load. It performs no work.

That's incorrect. The pick-up coil is the load.