STEORN DEMO LIVE & STREAM in Dublin, December 15th, 10 AM

[LarryC]

Of course. Do you understand what you just posted? Obviously not. Can't you understand that the power returned to the source is not dissipative power? Power delivered by the inductance and returned back to the source is not dissipative power. In this discussion we are only interested in dissipative power. Inductive power is not dissipative power. Only  power delivered to the active resistance (dissipative resistance, Ohmic resistance) is dissipative power. Only power causing Joule heating (Ohmic heating) is dissipative power. Only the power delivered to the active resistance, not to the inductance brings about Joule heating. Get it? Read first the scanned pages and try to understand them before posting them here.

Another delusional rant, but I'll answer some of your misleading questions.

Omnibus stated:
Can't you understand that the power returned to the source is not dissipative power?

I didn't state that, so show me the statement where the text states that power returned to the source is dissipative power? 


Omnibus stated:
Power delivered by the inductance and returned back to the source is not dissipative power. Only power causing Joule heating (Ohmic heating) is dissipative power. Only the power delivered to the active resistance, not to the inductance brings about Joule heating.

Text stated:
In an RL circuit, only a portion of the input power is dissipated(Ohmic heating). The part delivered to the inductance is returned to the source each time the magnetic field around the inductance collapses.

The text agrees exactly to what you stated. So why is the text wrong? Is this another case where all the text books, electrical professors, and industry are wrong and Omnibus is right?

Now, as I asked earlier.  Show the Page and list the book, showing that your formula's can be used for any circuit other then DC or AC resistive only.

Regards, Larry

 

[Omnibus]

Show the Page and list the book, showing that your formula's can be used for any circuit other then DC or AC resistive only.

The page is right in front of you. You posted it twice. I said it, you don't get it, so I'll repeat it--only the active resistance is responsible for the losses. Inductance is not responsible for the losses. Even if there is inductance and the circuit is not DC or AC resistive only, even in such a case the only parameter responsible for the losses is the active (Ohmic) resistance. That is because over a full cycle the contribution of inductance to the losses is zero. You have to cut that out and to avoid cluttering this thread with your muddled thinking. Taking a course at a local college may help you straighten out some of your confusion.

[broli]

@omnibus

Can you please share the data of your highest cop setup yet. Time, current and voltage columns are enough. Thanks.

[Omnibus]

@broli,

Unfortunately, I took apart the coil that was giving the best result (didn't keep the data either) but I think this one is equally as good:

[broli]

@broli,

Unfortunately, I took apart the coil that was giving the best result (didn't keep the data either) but I think this one is equally as good:

Thanks omnibus but I would like to ask one more favor. Can you make a reference test case without changing anything besides removing the coil and replacing it with a simple resistor that draws near the same amperage. This will tell me what's up and down so to speak.