STEORN DEMO LIVE & STREAM in Dublin, December 15th, 10 AM

[gravityblock]

Where's my Omni Power?  I want my Omni power, and I want it right now!

Interesting Tidbits #1, Omni Power was named after Ominbus in the overunity.com forum by LarryC.  When you here Omni power today, it is in reference to OU, which means there is more output returned than the input power applied, as defined by the new equation for power measurments that Ominibus shook the scientific foundation and shattered presently acceptable known theories which will re-write physics as it is currently understood.

Interesting Tidbits #2, There is Omni Power (OU) everywhere!

Just trying to add a little humor and to encourage the continuation of this research.  I apologize in advance if this post offends anyone.  It's all about research, observing, analyzing, understanding, and questioning everything.

Nothing wrong with having a good heated debate.

GB

[exnihiloest]

...
There is Omni Power (OU) everywhere!
...

Everywhere, like God.
The question remains: where can we plug God to power our houses?
I apologize in advance if this post offends anyone.   

[Omnibus]

[ author=LarryC link=topic=8411.msg246066#msg246066 date=1277089598]
Not true, that is a total lie.

Lets keep in mind that you first stated this: 'The funniest thing is that you don't realize that if I consider the cos(Phi) factor the OU effect I'm reporting will be way higher.'

The math I showed using cos(Phi) factor in my previous post proved that you are wrong, your OU is not higher with the True power formula(from the displayed text). In both cases True power is less than Omni power(from your excel formula's):

'True power at cursor b = 17 V  * .002 A * cos(88)     b = .002^2 * 63 Ohms * cos  (88)
                              b = 17  * .002 * .034899          b = .000004 * 63 * .034899
                              b = .001187                            b = .000009

Omni power at cursor b = 17 V * .002                       b= .002^2 * 63   
                              b  = .034                                b= .000252'

Isn't .001187 < than .034 and .000009 < than .000252 in Omni world?

But as usual, as you have done many times in the past, instead of being man enough to admit that you are wrong or show the math that is being presented is wrong, you decide to just state another lie.

It seems you have the delusional belief that just because you state an incorrect fact that people will believe you and you don't have to show any proof.
Homework for me? You did not even realize that the Cos of 1 to 90 angle, which is all less than one, would reduce the OU.


Regards, Larry

You'd do better to find some way to straighten out your confusion before continuing to clog this discussion with gibberish. Your calculations are wrong, I explained why and continuing to insist on them will not make them right.

[broli]

Oke omnibus I've used your data to graph instantaneous power of the supply and power being dissipated from the resistor which I took to be 63 ohms, correct me if I'm wrong on that one. Using this cop becomes around 15.

But I have to retract my previous comment on parasitic capacitance. Because this graph assumes that indeed the measured current is actually going through the resistor. The problem is how can we be absolutely sure about this. There are really two methods, one is a calorimetry test, which is not the most straightforward. And the other is to resort back to a non inductive resistor in front of the coil of about equal resistive value. If we assume that power will be divided we can only measure the current and then calculate power dissipated by this shunt. Since we're dealing with such high cops the power dissipated by the shunt alone should still be higher from what the supply has given.

Edit: Have re graphed the data with the correct resistance value posted below of. Now the average ratings are in line with the slope graphs from omnibus. Have also scaled the y axis up a bit to see the averages better.

[Omnibus]

@broli,

I think this answers the capacitance problem: http://www.overunity.com/index.php?topic=8411.msg245828#msg245828

Also, the active resistance of the coil is 11.4126Ohms while the resistance of the metal-oxide resistor is 99.7475Ohms.