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Overunity Machines Forum



GENERATOR- YOU DO THE IN/OUT POWER MATH

Started by magnetman12003, April 19, 2010, 09:16:15 AM

Previous topic - Next topic

0 Members and 5 Guests are viewing this topic.

DeepCut

FatChance, thanks for your help on the self-running.

The closest voltage-regulator i could buy is this one :

http://www.datasheetcatalog.org/datasheet2/a/0s922lq6p7gwsc2hhzx6z4e3pl3y.pdf

I bought this rocker-switch (DPDT version) to switch between supplies :

http://www.maplin.co.uk/Module.aspx?ModuleNo=2365

Plus i got the right capacitors/resistors to provide a 9V output according to this formula :

Vout = 1.25V(1+(R2/R1))+IR2

I'm sitting down tonight to try and make the circuit.


Thanks,

Gary.


DeepCut

OK the voltage-regulator circuit works and i had fun making it but ... no self-runner :( 

Not even with a 1000uF/35V cap.

The upshot is that you learn electronics whilst trying to achieve your goal i suppose.


Gary.

FatChance!!!

Quote from: DeepCut on June 14, 2010, 08:18:55 PM
Apparent COP = 15.0144/0.6678 = 22.48 !
This was your initial report on calculated COP. Seemed very nice.
It's really hard to make measurement errors giving a COP of 22.

Quote from: DeepCut on June 18, 2010, 06:00:21 PM
OK the voltage-regulator circuit works and i had fun making it but ... no self-runner :( 
Not even with a 1000uF/35V cap.
And there is no self runner, even though you seemed to have COP 22.  :o

My only question is: Where did you miss out in your wattage measurements? ???

If the difference between input/output is COP 22 then I really want to know
how you performed your measurements in detail?
You must have measured something 22 times wrong, to small or to big. How's it possible?
Can you please take new measurements by the assist of someone else qualified in the field?

I hope you still have the energy and goal for overunity research. Good going!!!

DeepCut

Thanks FC.

You may have missed a few posts, MScoffman explained why the COP was not 22 a few posts back because, although i was using Ohm's Law, ie; the resitance of the coil, to calculate the current, apparently the resistance of the coil measured in it's AC domain is not the same once it has been rectified to DC because of Inductive Reactance. So there's the error !

I'm now thinking perhaps transforming the DC output so the voltage drops but the current rises might do it but i have to check the numbers.


Gary.

mscoffman

@deepcut;

This is your engineering conscience speaking...
"Keeping you on the straight and narrow and away
from unnecessary developments in anti-grav." :D

---

Don't give up...The series regulator does an admirable job...except
that it is not efficient. It acts like an intelligent resistor, it produces
the correct voltage on the output by throwing away input power.
And another bad thing it dissipates that power in itself, so it requires
a worst case heat sink to work correctly. For example. Regulator in is
10volts in at 10ma = 100mW you throw away 50mW as heat, so you
have 5Volts at 10ma = 50mW. Note that the current is always nearly
the same for both input and output. That's how a series regulator is
supposed to work. Simple, low parts count, inexpensive and not efficient.

---

There are three ways to build a power conserving voltage converter.
Especially if you ve any kind of toroid capability. Any old toroid core
should work and you can wind this with plastic insulated hookup wire.

1) Use your voltage regulator to build a (boost) bucking voltage
converter by using a toroid as the inductor. This circuit is described
in the Application note Document for the series voltage regulator
you are using.

or

2) Use your toroid as a pulse AC transformer. Try 12 turn winding on primary
and 6 on the secondary. The primary connects to the motor coil output.
Have some extra lead length so you can adjust the number of turns from
instrument readings under load. These turns counts are on the low side,
so the transformer inductance will be on the low side, but it will demo
things so you can adjust correctly.

or

3) Switch a capacitor between the DC output and another
capacitor approximately twice that size on the input. The motor
itself should be capable of supplying you the "clock" signal to do
this. Adjust the capacitors.

---

You may be chasing your tail: Ie. getting closer and closer to unity
gain, but these circuits are not that complex, so you should not
be wasting your time. You should be able out read out the efficiency
now and then.

:MarkSCoffman