Captret - Capacitor and Electret

[ibpointless2]

So i have two circuits going on. Both are running the same type of red LED and both are using the same type of capacitor turned into a captret. When both batteries are connected to their circuits the battery voltage on both will drop. Now this is where they start to act different. The Charged "new" battery will keep going down over time, not very fast but it will go down. The "dead" battery will go up    Don't know but it does. One would expect that both batteries to drop when connected to the circuit and they do, but one would not expect the dead battery one to go up while still under the LED load. Even when the LED is left in the darkness or switch the LED out with a resistor or a electric motor and the same effect will happen. So makes these dead batteries that much better? will my charged new battery drain enough and become dead to where they will start to charge back up?

Why do the LED's even run? I've have them running on voltage above 20V and they don't burn out like you would expect.

When a capacitor is in series with a battery it will get full and make a open circuit, but the captret never shuts off.

So far all i know is that i got a LED light that will run off a "dead" 9 volt battery and keep running for infinite amount of time.


For even more explanation on the captret vs capacitor here is a video

http://www.youtube.com/watch?v=c6U7Lg95-2s

[broli]

So i have two circuits going on. Both are running the same type of red LED and both are using the same type of capacitor turned into a captret. When both batteries are connected to their circuits the battery voltage on both will drop. Now this is where they start to act different. The Charged "new" battery will keep going down over time, not very fast but it will go down. The "dead" battery will go up    Don't know but it does. One would expect that both batteries to drop when connected to the circuit and they do, but one would not expect the dead battery one to go up while still under the LED load. Even when the LED is left in the darkness or switch the LED out with a resistor or a electric motor and the same effect will happen. So makes these dead batteries that much better? will my charged new battery drain enough and become dead to where they will start to charge back up?

Why do the LED's even run? I've have them running on voltage above 20V and they don't burn out like you would expect.

When a capacitor is in series with a battery it will get full and make a open circuit, but the captret never shuts off.

So far all i know is that i got a LED light that will run off a "dead" 9 volt battery and keep running for infinite amount of time.


For even more explanation on the captret vs capacitor here is a video

http://www.youtube.com/watch?v=c6U7Lg95-2s

Can you draw a circuit of this, it's a bit hard to see where the wires are going, thanks.

[ibpointless2]

Picture of captret led driver circuit.

[broli]

Picture of captret led driver circuit.

Thanks, I managed to replicate it and it's quite interesting. Actually you don't need to use both main legs of the cap, it also works like seen below.

There's obviously no short between the top cap and legs so that's ruled out. However my friend suggested it could be picking up radio waves. I want to rule this out by putting it in a faraday cage tomorrow.

[nievesoliveras]

I tried a capacitor with a dead 9v battery and a led. It has not worked yet. I will let it connected a few days and see if the battery gains a charge.

The capacitor is a 2200uf 16v I took from an old motherboard. the battery had 2v when I connected it to the circuit.

Jesus