HeairBear, I do agree, yet u have to see the fact that water can be charged to the point of overload, it just has to be done at the right frequency and it WILL yield the anticipated results. Common, we have come so far already, just let me handle the rest of this It'll be good - I promise

Quote from: HeairBear on March 27, 2010, 09:52:25 PM
The meters will give you a false reading. The water itself is the cause of the problem. Any LCR meter is designed for typical capacitors, not water. If you could find a way to be certain of a real measurement, the numbers of the cell alone will matter very little, if any at all. As soon as any amperage goes through the water it's no longer a capacitor. That means to use the cell as a capacitor you would have to use an applied voltage of about 1 volt or less depending on the water.

Yes that is right, water isn't very isolating at all. However when using distilled water the capacity is measurable [althrough it obviously changes with temperature, water movement, vibrations and so on like you said]. But we were talking about isolated cells in this thread, may it be with a rubber sheet or with a layer of calcium.
I don't see a reason why the resistance of a capacitor should be much lower than it's reactance in that case.

I also don't know how my RLC-meter measures exactly. I see the problems when using direct current to charge a capacitor and measure by this way, but there can be many methods of measuring a capacitance, depending on the equipment available (charge time, discharge time, frequency behavior, circuits for resonance and so on).

More explanation (capacitance and other electronics 101 issues aside), let's go back to water.Why is common electrolysis so inefficient? It probably is because in electrolysis water is used as a conductor. With DC particularly, electricity flows in one direction. How do you expect to fracture the water molecule efficiently when u just use it to conduct electricity? You are not creating an imbalance in the molecule, you are just applying more current and add possibly chemicals to improve it's natural ability to conduct. But it is different when the electrodes are isolated and you leave the amps out (u need them anyways only if you want to use conductivity) and raise the voltage in order to create a HV DC field ... which in turn interacts with the electro magnetical properties of the water molecule (everybody following so far?) ... now quite frankly ... if I was the water molecule and was subjected to a HV DC field, quite frankly I would get pissed and would feel violated ... so there would a definate recation coming from me in response to the HV DC field ... do not underestimate the power of pure voltage, it has quite some kick under the hood. Now once again, water can be polarized but it has to happen in very short successive bursts (hence the pulsing of the field) ... u keep charging and adding to that charge ... well until the water no longer can keep it and yields to the electrical forces ... thats when we get the results we want.

Which electrode does the current leave from? Stupid question, I know... Just checkin

according to my findings from negative going to positive, however you will always find people who would like to argue that lol

why were u asking? ... nothing travels in my cell ... there is a big 'no current allowed' sign on it lol

... correction ... the only thing travelling is the water molecule being pulled apart from each electrode in a different direction with each pulse train.