So the length of the wire is the name of the game.

Seems odd. In audio crossovers, a coil, no where near a tenth of a mile long, wont let much above its -3db crossover point, at 6db per octave, at 20khz,  the signal will be down 54db, with a crossover point of 100hz.

But, we are talking about something else here. We are talking about how fast the charge cycles through the coil(secondary here) from end to end. Thats just guessing from the formulas you have described.

What would happen if you wind the flat sec. counter clockwise? And why.  =]

And can you have 2 or mor smaller sec coils and put them in series? Or would their proximity to each other be adverse?

Trisil   I attached the spec sheet in pdf.  Just got them today.  Gota see what they can do.  Forest posed a file that shows the difference between TRISIL and TRANSIL. 

Thanks DB    Dat Boy   =]

mags

Quote from: Magluvin on December 02, 2010, 08:20:36 PM
So the length of the wire is the name of the game.
Seems odd.

mags

You are focusing on just one problem here, but there are others problems like:
-primary cap what value and what voltage to be discharged to few turns of primary
for example lets say that Up=2kV and Cp=0.1uF Lp=10uH (frez=159kHz)
this will give impedanse Z=sqrt(Lp/Cp)=10 Ohms
if we ignore transient resistance of controller, peak primary current will be
Ip=Up/Z=200 A ! But if I choosed Cp=1uF (now Z=3,16 Ohms) to have Frez=50kHz than peak primary current would be I=632 A ! You SEE THE PROBLEM!
Thats why we need thick primary wire, to reduce loosses!
-problem of hiting the resonance of secondary to get highest voltage on secondary
Because of this problem you have to have one more inductivity with slider,in series with primary, to adjust resonant frequency of primary

And thats not all...

Quote from: delboy on December 03, 2010, 02:22:34 AM
You are focusing on just one problem here, but there are others problems like:
-primary cap what value and what voltage to be discharged to few turns of primary
for example lets say that Up=2kV and Cp=0.1uF Lp=10uH (frez=159kHz)
this will give impedanse Z=sqrt(Lp/Cp)=10 Ohms
if we ignore transient resistance of controller, peak primary current will be
Ip=Up/Z=200 A ! But if I choosed Cp=1uF (now Z=3,16 Ohms) to have Frez=50kHz than peak primary current would be I=632 A ! You SEE THE PROBLEM!
Thats why we need thick primary wire, to reduce loosses!
-problem of hiting the resonance of secondary to get highest voltage on secondary
Because of this problem you have to have one more inductivity with slider,in series with primary, to adjust resonant frequency of primary

And thats not all...

Yes! buddy your obsoletely correct! 

But! i think instead of saying a lot of things like that. then

we can say 'it only needs some balance'

And that's all 

joke         

Quote
You are focusing on just one problem here, but there are others problems like:
-primary cap what value and what voltage to be discharged to few turns of primary
for example lets say that Up=2kV and Cp=0.1uF Lp=10uH (frez=159kHz)
this will give impedanse Z=sqrt(Lp/Cp)=10 Ohms
if we ignore transient resistance of controller, peak primary current will be
Ip=Up/Z=200 A ! But if I choosed Cp=1uF (now Z=3,16 Ohms) to have Frez=50kHz than peak primary current would be I=632 A ! You SEE THE PROBLEM!
Thats why we need thick primary wire, to reduce loosses!
-problem of hiting the resonance of secondary to get highest voltage on secondary
Because of this problem you have to have one more inductivity with slider,in series with primary, to adjust resonant frequency of primary

And thats not all...

That's the reason, Delboy, That in HF resonators we prefer at using Large inductance, small capacitance because at "same" resonant apparent power losses are enormously smaller.
Or to put it another way, there is not a way (except superconductors) to achieve a large current resonance with the same strentgh and at same energy expense as small current one.

Quote from: baroutologos on December 04, 2010, 03:53:24 AM

That's the reason, Delboy, That in HF resonators we prefer at using Large inductance, small capacitance because at "same" resonant apparent power losses are enormously smaller.
Or to put it another way, there is not a way (except superconductors) to achieve a large current resonance with the same strentgh and at same energy expense as small current one.

You are talking about secondary, while I was pointing out important things about primary.
-It will be expensive primary cap(paarallel and series combinations), because current will be order of few hundreds of Amps.
-It will be cheap primary, because it is few turns of copper pipe
-It will be expensive secondary , because it is too much in lenght, and big diameter, thick wire etc.
-It will be cheap secondary cap because it can be metal ball of proper dimensions

SEE HOW THINGS HAVE DIAMETRICAL POSITIONS

And of course, inductive connection of primary to secondary should be tight, but as usually it is not like that. Anybody give me link of your Tesla Coil with close primary windings to secondary, without as usually over 1 inch distance. Give me example of 1mm close connection primary to secondary.