so when are you guys going to demonstrate overunity ?
The rest of us are waiting.
Wayne has already posted that it is a working overunity device.
Of course, my car starts when I want it to and it keeps runnimg.
Somethimg Waynes device cant do.

i owe you guyr an apology. if yott want to slobber over each other, thts okay.

Quote from: mondrasek on June 18, 2012, 03:24:01 PM
@telecom,

I'd be happy to try and explain the exact sequence of operation of the machine if I only knew what was unclear.  The patent spells everything out very clearly to me, but I understand that is not the case for everyone.  Playing with the drawings I have made and the calculations have also firmed up some things for me.  Maybe if you had some specific questions?

Maybe the picture below is a good start.  The ZED on the left has no lift.  The ZED on the right has full lift and has stroked to it's mechanical limits.  So from this starting point the pressurized water at the bottom of the center chambers would be allowed to flow from the right ZED to the left ZED freely through the pipe shown.  Once half the water has been redistributed the system reaches a balance and both sides are at the same water pressure.  Now the pump (circle in the drawing) would begin to pump the second half of the water from the right ZED to the left ZED.  While this second half of the water transfer is happening, the left ZED will become buoyant and begin to rise.  At the same time, the right ZED will have lost it's buoyancy and begin to sink.  When all the water has been transferred, you have the mirror image of the picture below.

M.

Thank you,
but were is the proverbial air bubble from the post 108?
If its in air gaps, is the air pressurized?
Also, to collapse quickly, is the air gap supposed to disappear?

Quote from: LarryC on June 18, 2012, 04:53:36 PMI've improved the spreadsheet to make it easier to understand.

You forgot a very important fact: the air/water exerts pressure on the surface of the risers in every direction, that means, also down on the riser below it.
The correct formula is subtracting force from the riser above (Outer surface of Riser X). Also, the pod won't be fully submerged as described in the patent and several drawings...

I have attached the corrected spreadsheet.

Quote from: KanShi on June 19, 2012, 01:10:49 AM
You forgot a very important fact: the air/water exerts pressure on the surface of the risers in every direction, that means, also down on the riser below it.
The correct formula is subtracting force from the riser above (Outer surface of Riser X). Also, the pod won't be fully submerged as described in the patent and several drawings...

I have attached the corrected spreadsheet.

That would be double dipping. The pod is Archimedes and is calculated using volume or pressure differential formulas, please see my reply in 563.

Regards, Larry