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Overunity Machines Forum



Negative Inductance and measure of Magnetic force.

Started by synchro1, November 19, 2017, 08:20:57 AM

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synchro1

The simple oscillator I described will return the neutralization pulse %100 with no loss what-so-ever. The dividends show when you rev it up. It could work a compressor pump; Any additional power you added would be returned by an equal share of free power.

synchro1


In addition to magnet strength, the other parameter is the neutralization coil construction. View this video:


Remember; Raising coil inductance by increasing core permeability has the same effect as adding more wire!

https://www.youtube.com/watch?v=cbFqVh7GdGk

synchro1

Here's another way to look at it; We can double the magnet strength and still maintain the break even COP. Think about this! This ratio would stay the same with an attraction solenoid.


If we double the magnet strength and match the size and inductance of the neutralization coil, and increase the input to balance the force, the power exchange remains equal. However, if we double the magnet strength in the attraction solenoid, we double the mechanical output force to the flywheel; While the input is still entirely recovered!

The same ratio applies to the neutralization oscillator. The crank shaft in the solenoid serves the same function as the spring in the oscillator that holds the discs apart. The attracting magnet pulls on the flywheel instead of pushing against a spring. The oscillator can compress a diaphragm in a compressor pump and store power that way instead of heating up a spring. Simply replacing the spring with a tiny hydraulic pressure pump would put the COP OU.



synchro1

This attraction oscillator hydraulic pressure piston pump could power a turbine and generate boundless electricity for free depending on the magnet strength! the spring action comes from back pressure from the hydraulic head.

synchro1