In figure 2 the poles are the faces of the magnet.  In other words north is either the right curved face or the left curved face.  And of course the opposite pole is the other face.  I have many of those magnets from small DC motors.  The poles are not on the ends.  I just verified this with a compass.  For a few dollars you can buy a compass and then you don't have to keep guessing where the poles are.

Quote from: kolbacict on November 25, 2019, 07:34:20 AM
Only I still do not understand anything.

The matter is, no one really understands, and this is the beauty of it.

Quote from: ayeaye on November 24, 2019, 06:16:49 PM
See the figure below, how can the shield magnet shield by the Coulomb model? By the Coulomb model a magnet is just two poles, both with a perfectly spherical field. And this is the only model that is symmetric. Say that the vertical N-S there is the shield magnet. You see that by that model there is nothing in between the north poles of two magnets, thus no shielding. When there is shielding, and evidently there is, then the fields must be somehow asymmetric, that is the fields of the poles must be different from spherical.

Ah, i'm sorry, this was not the shield magnet, the Citfta's was like this, was it?

S            S
     N  S
N            N

Anyway, you get an idea, in the Coulomb model there is nothing in between the repelling poles.

Coulomb only applies to the magnetic vector of the electric field.
Not the ferromagnetic field
Atomically, and molecularly, there are discrete energy states which can persist
outside of the spherical model.
Most commonly, a permanent magnet takes on the field shape of 2 inverted muffins
the center having no magnetic field at all, and almost always one "muffin top" larger than the other.


This natural asymmetry is independent from the phenomenon of S pulling more and N pushing more

Quote from: sm0ky2 on November 26, 2019, 12:50:13 AM
Coulomb only applies to the magnetic vector of the electric field.
Not the ferromagnetic field

Right but, the Coulomb model is sometimes also used for magnetic fields, for simplified calculations. Why is that important, is that the Coulomb model is the only model that is completely symmetric. Thus, when anything differs from the Coulomb model, the field may be said to be asymmetric.

The real magnetic field differs from the Coulomb model, and thus isn't completely symmetric.

QuoteOn the figure 2, the poles of your magnet are up and down?

sharp ends up.