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Overunity Machines Forum



re: energy producing experiments

Started by Delburt Phend, February 04, 2017, 09:31:19 AM

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magneat

Quote from: Toolofcortex on January 10, 2020, 12:44:57 PM
https://revolution-green.com/earth-engine/

See the comments here.
it's hard to believe that a team of such professionals would look for suckers...

Toolofcortex

It seems unreal they would dare to pull off such a scam.

Then again, does the work of a paid hoaxer even have a meaning?

Or maybe I am just imagining conspiracies and this guy got inspired for a scam I dunno.

Bummed out because it seems like everywhere you go its a tough road to OU, Wht do you expect LOL?

Ou is like Jedi and Sith status almost, and this is the far flung galaxy.

but whats this what Pierre Cotnoir first showed?

A while ago.

If Chas Camplbell wasnt pulling any tricks and really self looping in that video it was definitly OU.

The video where it start, "were filming"...

Toolofcortex

https://www.youtube.com/watch?v=2qyvX9j5i3U&t=83s

Actually, someboy should analyze this by video and see the speeds.

It seems like the light was still lit after that as well.

magneat

Quote from: Toolofcortex on January 10, 2020, 11:41:13 PM
https://www.youtube.com/watch?v=2qyvX9j5i3U&t=83s

Actually, someboy should analyze this by video and see the speeds.

It seems like the light was still lit after that as well.

The Chas Campbell Gravity Wheel may well be working, but to understand the OU principle of a mechanical generator, I like F.M.CHALKALIS ENERGY MULTIPLIER more - https://www.youtube.com/watch?v=iHhZZ9DuzK4&feature=emb_title
This video shows all the OU classics for a mechanical generator.
only one moment, imho, is not correct for F.M. CHALKALIS - why does it give an impulse to the flywheel at the TOP point of the trajectory, when according to theory the impulse should be applied at the moment when the "body" speed is maximum, i.e. at the BOTTOM of the trajectory?

and also, imho, on rollers that give an impulse to the pendulum, you need to add a flywheel.
then the drive electric motor can be taken of small power, energy will accumulate in the flywheel, and in the pulse will be transmitted to the pendulum.
it is also unclear why the goods are placed in the middle of the radius of the pendulum, it is more logical to place them at the end of the radius, the torque and stored energy will be more ...
then the calculation of the parameters F.M. CHALKALIS ENERGY MULTIPLIER can be done according to elementary formulas of classical physics ...

F.M. CHALKALIS ENERGY MULTIPLIER can serve as a training tool for understanding the OU principle of a mechanical generator.
for the training stand, the design can be greatly simplified - take an inflated bicycle wheel, strengthen one load (several loads?) from the inside of the rim, fasten (stick?) several strips of rubber from the outside to the tire cover through which from the drive roller (with flywheel) a force impulse will be transmitted to the wheel with the load (s).


The Chas Campbell Gravity Wheel, imho, is also a working structure, just not as transparent as F.M. CHALKALIS ENERGY MULTIPLIER.


p.s. for any OU generator, you need the correct calculation of the parameters, and the correct setting, like for any other (ordinary) mechanism. and then later, some "OU seekers" have statements: "this OU is not working" ....

Delburt Phend

I think that the despin concept is in some way incorporated into any wheel that produces energy. So I will outline the despin concept.

It takes the same amount of force, applied for a period of time, to make a mass move around the arc of a circle as it does to make the mass move in a straight line. So the math used for the arc of the circle is the same as that used for a straight line. Which is F = ma.  When a mounted rim has a certain amount of force applied for a certain amount of time the mounted rim has a certain amount of momentum.

A 9 kilogram rim can be accelerated by wrapping a weighted string around the rim; and a one kilogram mass can be placed on the end of the string. After the one kilogram mass has dropped .5097 meters the system will have a velocity of 1 m/sec.

A 10 kilogram rim mass wheel moving one meter per second, in the arc of a circle, has 10 units of momentum. When a 1 kilogram mass swings out on the end of a string (as in the cylinder and spheres) it will have 10 units of momentum when the rim's motion is stopped.

This is proven to be momentum because the 1 kilogram can restore all the motion back to the rim if the 1 kilogram is left attached. Small masses can not give their energy to larger masses.

Ten kilograms moving 1 m/sec (the rim with spheres attached) is 5 joules of energy.

One kilogram moving 10 m/sec (the spheres) is 50 joules.

The one kilogram moving 10 m/sec can be sent upwards 5.097 meters.

So we start over . A 9 kilogram rim can be accelerated by wrapping a weighted string around the rim; and a one kilogram mass can be placed on the end of the string. After the one kilogram mass has dropped only .5097 meters the system will have a velocity of 1 m/sec.  This one meter per second, for the 10 kilograms, bring us back to the  point where we transferred the motion of the rim to the smaller spheres. The smaller spheres are then sent upward 5.097 meters.  And we have 5.097 - .5097 = 4.587meters left over.

Now the question for all these flywheels is: How do you gain an energy increase without releasing the spheres and letting them rise. They need a tower for the spheres to rise; and then catch the spheres for a slower driving descent.   

Another question I have is: How can all these people be so close and not try wrapping their flywheels with a weighted string and see if it works.