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Overunity Machines Forum



THE RANT ROOM

Started by ramset, April 25, 2017, 04:30:05 AM

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0 Members and 12 Guests are viewing this topic.

partzman

For those interested, this is a more comprehensive explanation of my sim "Lenz Reduction with Constant Current Load". 

Transformer T1 is made up of identical primary and secondary windings namely L1 and L2 with a coupling factor K = .8 .  Neglecting ohmic losses in all the following, L2 is first charged to 100ma and held at that current by constant current inductor L3.  The energy in L2 is now .1^2*.0029/2 = 14.5uJ.  The primary L1 is now charged from supply V1 until it reaches 100ma.  Due to the fact that the secondary L2 is held charged via a constant current source, it will not present any opposing emf to the primary because there is no change in secondary current and thus the primary will "look like" a 2.9mH inductor to the power supply.  So, the energy then contained in the primary is .1^2*.0029/2 = 14.5uJ.  In reality, the primary inductance will appear slightly higher for the reason explained below.

We have now invested 29uJ to charge both primary and secondary windings resulting in equal in-phase currents.  IOW, we now can connect the primary and secondary in series or L1+L2 and in effect we have an inductance of 10.46mH charged to 100ma.  This results in a net energy of .1^2*.01046/2 = 52.3uJ.  Therefore, the net COP = 52.3/29 = 1.8 .  The maximum theoretical COP with this device is 2.0 with a perfect coupling factor K=1. 

During the time L1 is being charged, a positive voltage will appear across L2.  The polarity of this voltage will affect the current L3 due to di=Eavg*dt/L.  In this case, there will be a slight current loss in L3 thus a loss in energy which must be accounted for.  This slight change in secondary current will also make L1 appear to be slightly higher in inductance.  If the voltage polarity across L3 is negative, there will be an increase in the constant current or a slight gain!

As a side note, the two following formula can be used to calculate the aiding or bucking inductances of two identical windings on a common core if the coupling factor and the inductance of one winding is known.  The buck inductance is Lbuck=((1-k)*2)*L1 and the aid inductance is Laid=(1-((1-k)/2))*4L1.  These can also be solved for k if certain buck or aid inductances are required.  These calcs do not take into account losses or unequal winding inductances.

By applying the above, it is interesting to see the results of bucking coils with K=.5 and then determine what core topology would be required to obtain that k factor.

IMO, there is enough info here for anyone to construct an OU device if they are willing.  Keep in mind that there are many variations possible with this concept.

Regards,
Pm

Edit: Typo

onepower

Chet
QuoteAs stated before no one has ever found an OU claim at Overunity research that would survive the separation from the bench power supply ,batteries  ,or closer scrutiny. always the error has been found .
many times partzman has thought he was onto a gain mechanism [above example] which was truly an anomaly [yes did seem to show OU],yet none has survived the ultimate test....An ability to selfrun with no input from external sources.

Personally I prefer to use input/output capacitors on real circuits for the reasons you pointed out above. So while I may have more failures and non-working concepts or devices I know exactly where I stand in reality. As well with HV circuits of 10 kV or more the input/output can be measured with spark gaps of a known distance (voltage) and photo-detectors (current intensity). Not so much as an exact standardized measurement but more so a meaningful comparison which is what were looking for in my opinion.

It's all work in progress and time ultimately tells what works and is real and what is not so much.

Regards

ramset

Onepower,I have to be honest...I love your thoughts on how to make and log advancements.
perhaps you could do a short tutorial on this capacitor method ?
I know you were mentioning a vid of some kind.
May seem very simple to you ...?  however we need all the help we can get and the more experimenters who collect good Data the better !!... [this is one very big reason for the light bulb temperature to output Data.
??






Whats for yah ne're go bye yah
Thanks Grandma

onepower

Chet
QuoteOnepower,I have to be honest...I love your thoughts on how to make and log advancements.
perhaps you could do a short tutorial on this capacitor method ?
I know you were mentioning a vid of some kind.
May seem very simple to you ...?  however we need all the help we can get and the more experimenters who collect good Data the better !!... [this is one very big reason for the light bulb temperature to output Data.
??

There is not much too it and in it's most basic form we replace the source with a big capacitor then charge another identical capacitor on the output.

Think of it this way, we have an input capacitor, a black box circuit and an output capacitor. If in fact the black box circuit outputs more energy than was input then the output capacitor will charge faster than the input capacitor discharges. Once a test cycle is completed we simply do a quick calculation, U=CV^2, on each capacitor to tell us how much energy it contains. I do this because capacitors do not mislead and regardless of what happens in our black box circuit we can always have an exact measure of how much energy went into the circuit and how much left it.

Once we have nailed this basic concept down then we can start to think about how to move the energy in the output capacitor back to the input capacitor to close the loop. When I started I was simply using a high efficiency joule thief (boost converter) on the output capacitor to pump it back to the input capacitor which worked well enough. The boost converter tested at around 90% efficiency so I used a 10% loss in my calculations to compensate. If the capacitors voltage starts running down faster than 10% then we know were moving in the wrong direction.

Regards



ramset

remarkably simple ...
and also one reason I was told to use thermometers instead of meters at times [certain frequencies completely effect meter accuracy or dependability..and all the fancy equipment too at times..... Noting the temperature of a bulb [as a starting point] ...priceless info for experimenters.
That is to say if I know my experiment uses X input [or come to a conclusion where i define COP
do a simple thermometer test of Bulb at this assumed COP input. 
then play all my experiments ...and always checking bulb temp [to benchmark or "control"]
yes some will say "oh there is energy dissipated [heat] in other parts which needs adding to COP
yes I agree...and that is where thermometer gets used too
lossy cardboard Box...put bulb at assumed COP input claim in box [nothing else] and run
bulb will only be able to heat box to certain temp ...will stabilize do to losses [ambient stealing energy thru lossy cardboard box. [worlds most efficient use of electricity making heat ....unity]take bulb out of box...and put entire POC DUT [proof of concept/ device under test ] into box
a race against the worlds best heat maker.. "unity".
you beat "unity" this way [same COP input as resistor  ..higher temp ?? Katey bar the doors...you get the worlds attention in a heartbeat.
NOBODY HAS BEATEN THE RESISTOR ....for making heat.. UNITY stares us in the face.
[it is a given temperature in a cardboard box]
I was told the worlds most efficient use of electricity is making heat.. 100% efficient [or absolute unity ] The common resistor does this ...since all losses go to heat.. when heat is the goal... resistor is Top dog or king [a bulb comes close so its good to play with...yes it is possible to make bulbs brighter playing with frequency...but brighter and hotter
at same input ??

anyhow...thanks for comment.. anything that helps the open source community do better experiments and make advancements based on benchmarks or accurate measurable goals....priceless contribution to the open source community. 

knowing where your going without knowing where you started [in testing claims]?
not even in my frame of reference [as an option]

just one mans opinion...
thx Chet
Whats for yah ne're go bye yah
Thanks Grandma