Ghazanfar Ali Generator - Utlilizing trapped energy

[Ghazanfar_Ali]

I hope ur sig gen was not connected with 4700uF. and if not then definitely ur 1mH damaged ur sig gen. coz it gives a kick off of high voltage back to the source producing pulses.

[EMdevices]

This topic has come to my attention and I can provide some insight into the operation of this circuit.   I simulated it with LTspice as can be seen below.


My primary comment is that this circuit is primarily a modified BOOST converter topology, lacking only the diode and perhaps the output smoothing capacitor.    The parallel capacitance of the coil is always present with any real coil, and perhaps this capacitance is enhanced on purpose by Ali.   Due to proper timing and resonance, the switching occurs at zero voltage (correction, at zero current technicaly which is very efficient), so it wastes very little power in the switching phase.      Here's a link if you're interested:   http://en.wikipedia.org/wiki/Boost_converter

The real question is:  where is the power coming from?

The answer is:  the power comes from the 50 V supply, wheater it is a battery, or a large capacitor, or a power supply.

I'm wondering, do we have a claim here that using a capacitor, the circuit runs indefinitely and the capacitor stays charged up?    If that's the case then this would be very significant!

EM

PS.   The blue curve in my simulation is the current defined positive into the (+) terminal of the power supply V1, so when we see the negative ramp down while the switch is on, that's when the inductor is charging up magneticaly and current is increasing according to dI/dt = V/L approximately, and upon switch off, the inductor supplies it's energy to the load producing the kick-back.   The red spikes are the kickback voltage across the load resistor coming from the inductor.   However, due to capacitance in the circuit the inductor reverses polarity and the voltage drops down to zero, and that's when we switch, so this circuit is operated in the zero voltage switching mode (corection, it is switched at zero current see the blue curve), which is very efficient.     If we do not waste a lot of energy from the input power source (V1 in this case)  we can replace it with a capacitor and have it seemingly run by itself, but the energy in the capacitor will deplete over time, much like the Joule Thief circuits.

[forest]

This topic has come to my attention and I can provide some insight into the operation of this circuit.   I simulated it with LTspice as can be seen below.


My primary comment is that this circuit is primarily a modified BOOST converter topology, lacking only the diode and perhaps the output smoothing capacitor.    The parallel capacitance of the coil is always present with any real coil, and perhaps this capacitance is enhanced on purpose by Ali.   Due to proper timing and resonance, the switching occurs at zero voltage, so it wastes very little power in the switching phase.      Here's a link if you're interested:   http://en.wikipedia.org/wiki/Boost_converter

The real question is:  where is the power coming from?

The answer is:  the power comes from the 50 V supply, wheater it is a battery, or a large capacitor, or a power supply.

I'm wondering, do we have a claim here that using a capacitor, the circuit runs indefinitely and the capacitor stays charged up?    If that's the case then this would be very significant!

EM

PS.   The blue curve in my simulation is the current defined positive into the (+) terminal of the power supply V1, so when we see the negative ramp down while the switch is on, that's when the inductor is charging up magneticaly and current is increasing according to dI/dt = V/L approximately, and upon switch off, the inductor supplies it's energy to the load producing the kick-back.   The red spikes are the kickback voltage across the load resistor coming from the inductor.   However, due to capacitance in the circuit the inductor reverses polarity and the voltage drops down to zero, and that's when we switch, so this circuit is operated in the zero voltage switching mode, which is very efficient.     If we do not waste a lot of energy from the input power source (V1 in this case)  we can replace it with a capacitor and have it seemingly run by itself, but the energy in the capacitor will deplete over time, much like the Joule Thief circuits.

And it still WILL BE OU! It only need to run at 50V level long enough , much longer then initial time used to charge capacitor. What is your simulation showing after a hour or two (simulated)?

[poynt99]

EM,

You need to replace V1 with a 4700u capacitor, charged to 50V. Then run the simulation; if the oscillation persists, then you have replicated Ali's simulation. If it "falls off" as it did in my simulation, then you are at the same point I am at right now.

Still waiting for Ali to upload a working PSpice version, OR a video showing his bench build oscillating indefinitely.

.99

[duff]

I'm wondering, do we have a claim here that using a capacitor, the circuit runs indefinitely and the capacitor stays charged up?    If that's the case then this would be very significant!

EM

EM,

That is the claim.

see here: http://www.overunity.com/7679/selfrunning-free-energy-devices-up-to-5-kw-from-tariel-kapanadze/msg311237/#msg311237