Kapanadze Cousin - DALLY FREE ENERGY

[verpies]

There should be a signal at pin 10, even without the resistors...

That's where you are wrong. 
Pin 10 is an open emitter output and without V_CC on the corresponding collector (pin 11) or a resistor pulling the pin 10 down, there will be no voltage variation on it.

It is true that a MOSFET driver is not necessary for a signal to appear there, though.  However if the input of that MOSFET driver is shorted inside the chip, then it will inhibit or burn out the TL494.pin10.

Also, for alternating push-pull outputs, pin 13 must be connected to pin 14.

Finally, are you sure that CH2 of your scope is functioning properly?

I hope that the TL chip is still OK, as it's not going to be fun if I have to replace it, already.

You should have several of these chips on hand.
If you don't have any, then you should know that you can pull them out of many broken ATX PC power supplies.  They are usually OK even if the PC power supply is bad.

[itsu]

Here the link to Nick's latest video showing the pin 10 output only:
https://www.youtube.com/watch?v=irIKzaCY1Q8

It seems strange to me that you can turn up the duty cycle on that pin 10 signal to about 98%.

Itsu

[verpies]

It seems strange to me that you can turn up the duty cycle on that pin 10 signal to about 98%.

Yes, such variation should be possible only when pin 13 is grounded.

[verpies]

For anyone interested, here is the TL494 schematic with separate dead time and duty cycle adjustments:

[Grumage]

For anyone interested, here is the TL494 schematic with separate dead time and duty cycle adjustments:

Dear Verpies.

That's a great start! How about going one step further and add the driver section? One suitable for both
MOSFET or IGBT.

If such a diagram could be prototyped I might even jump into the " affray " again, knowing that at least one part of it would work correctly!!   

Cheers Graham.