Re-Inventing The Wheel-Part1-Clemente_Figuera-THE INFINITE ENERGY MACHINE

[hanon]

Hello Hanon,
as already had occasion to say in another post,
the poles really have to be opposed North North, and thankfully you realized that this configuration is present in most circuits claiming excess energy production.
The patent Figuera we discuss here is not even 100% efficient however is of extreme importance the concept that explains figuera!
I also think that few people understand how to use the capture coil.

In my video showed that with only one turn, it was possible to capture bifilar 2Amp the generating coil, which means that the generator coil induces in each turn of a coil bibifilar 2Amp.
therefore if would add two independent loops  in parallel these same loops would capture 4A .
It is obvious that the coils being in parallel with resistance not risen,
what Figuera tells us is that we can put several independent coils and sum
the product of the catch coils.

bye

Hi Nelson,

I suppose that you are referring to this video that you uploaded some weeks ago: https://www.youtube.com/watch?v=hQM_Zg-R8LI

Please could you describe in some detail the test you did in that video in order we could replicate your test. I can see that you used a stator from an old motor.

I suppose that you wired the coils to be facing North-North and then you placed a bifilar coil (with one turn) in the middle. Could you tell us some more data? What input pulsed DC current did you use? Input:V=12 Volts, I=0.55 Amps, right ?
I think you pulsed the input current, am I right?, What frequency of pulses did you use? What are those capacitors for? (sorry if I am asking any silly question)

What happen if you do not use a bifilar coil and you just use a single coil? Did you have to move the induced coil in order to find the best place to collect that energy? What is the meaning of the measure of 44 Amps when you clipped the iron core? (I don´t understand this part)

Thanks in advance. I really appreaciate your help and your wise tests !! Thanks


Avenger: I have watched carefully your photos. What value of the 8 resistors are you using? Maybe your are using a very high value in those resistors. As a rough guess: if each electromagnet have 3-4 ohms of resistance then you can use 8 resistor each with 3-4 ohms

[shadow119g]

hanon,

After reading the "bucking."
I think I needed to wind one half of the two opposing coils opposite to each other?
The center coil does not matter?

Has anyone done this?

Shadow

[nelsonrochaa]

Hi Nelson,

I suppose that you are referring to this video that you uploaded some weeks ago: https://www.youtube.com/watch?v=hQM_Zg-R8LI

Please could you describe in some detail the test you did in that video in order we could replicate your test. I can see that you used a stator from an old motor.

I suppose that you wired the coils to be facing North-North and then you placed a bifilar coil (with one turn) in the middle. Could you tell us some more data? What input pulsed DC current did you use? Input:V=12 Volts, I=0.55 Amps, right ?
I think you pulsed the input current, am I right?, What frequency of pulses did you use? What are those capacitors for? (sorry if I am asking any silly question)

What happen if you do not use a bifilar coil and you just use a single coil? Did you have to move the induced coil in order to find the best place to collect that energy? What is the meaning of the measure of 44 Amps when you clipped the iron core? (I don´t understand this part)

Thanks in advance. I really appreaciate your help and your wise tests !! Thanks


Avenger: I have watched carefully your photos. What value of the 8 resistors are you using? Maybe your are using a very high value in those resistors. As a rough guess: if each electromagnet have 3-4 ohms of resistance then you can use 8 resistor each with 3-4 ohms

Hi Hanon,
I now my english is not the best but i will try to respond to your questions.

The two main coils in the stator are not bifilar.
One of this coil have more turns like other 1:3 ratio in relation to the other.
The connection of this coils to each other is CCW CCW.

The  bifilar white turn that is near the bigger coil is not connected to the circuit , is only to show how much current is possible capture by a single bifilar turn .
I show in the video the meter measure the core to show what figuera explain in their patent ; if we put a coil made my 100 single turns bifilar in parallel not in series, we will sum all the inducted power in ever single turns of the coil without drag the system . See the collector coils like a cell that you have to combine like a battery cell

Yes is pulsed dc 12v battery and the frequency is about 1 to 3 khz but will depend of a mechanical relay so is not linear. But observe quite well
in this video the shape of shot https://www.youtube.com/watch?v=SALlSg972y8. What you see ?  the square wave generated by the relay carry a modulated wave pay atention  i know the video is not the best but i think you will see

The caps   How can you storage radiant energy in a electrostatic container   .
Like i say before the figuera patent is only good to understand some principles . 

PS- in relation at using a resistor at commutation system is better replace the resistors by coils with the same value . Trust in my tip

I hope a can help with my contribute .
Thanks

[AVENGERS]

I found the bad solder connection, I missed something somewhere, every component connection has 12volts, plus or minus half a volt, even the coils, but no electro magnetism. When I disconnect from the board and put + & - to one of the coils I get a strong electro magnet. All comments & suggestions & advise are always welcome.
Thank You, All
AVENGERS

[hanon]

 Avenger,

You are using as resistor 10 Kilohms and 5 Kilohms  ¼ watt. This is not good!!  You should design the resistor value to let circulate as high current as you could. For example a range between 0.3 A as minimun and 3 A maximum. Let suppose you have all the resistor with 5 ohms. The minimum resistance will be with zero resistor and just the resistance of each electromagnet: let say I = V/R = 12 volt/5ohm = 2.4A. The maximum resistance will be when crossing the 8 resistor + electromagnet resistance : 8*5 + 3 = 43 ohms. Then I = V/R = 12 volt/43 ohm = 0.28 A. The wattage of the resistor must be calculated as : P =I^2·R = 2.4^2·4 = 29 watts.

With your resistors with 10000 ohms, you will just get a current of I = V/R = 12/10000= 0.0012 A just with just one resistor!!. Not good. Please upgrade your resistor to something in the range of 3- 4 – 5 ohm