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Overunity Machines Forum



Single circuits generate nuclear reactions

Started by Tesla_2006, July 31, 2006, 08:15:00 PM

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0 Members and 10 Guests are viewing this topic.

aleks

Quote from: Yucca on May 22, 2008, 04:43:24 PM
One more thought: If the beta manifests after 20ms and that power is fed back to the rod then the system will oscillate at around 1s/20ms=50Hz.... coincidence.... :o
And it will look like sine wave summed with DC. ;) (due to log-based gaussian pulses summing with overlap). So, it's probable that this system is capable of self-run driven by naturally lagging output. If capacitors are charged fast (probably some clever arrangement can be used for that) then this system won't need MOSFETs at all - just a switching system that fires capacitor energy.

Another thing to note: if this system delivers potential energy, then it is safe and won't heat much (beside what carbon rod discharges produce). Even if Juan's device was designed as 60kW, it is very likely that it was never tried at such load. Of course, this suggests that beta is not a driving force - otherwise this device will explode and evaporate quickly if 60kW worth of beta is generated (just imagine where it should go).

So, it should be some "sentry" potential generator. In this case magnetic field amplification is a good guess: in the absence of connected load it won't do any harm beside accelerating some local ions and electrons.

Inventor81

*poke*

notice the mutual inductace relationship for all the toroids.

Or Torrids

Or even Torridos.

Avoid Tostitos.

aleks

One another thing bother me also. E.g. I can see how a permanent magnet rotor can induce current in phased stators, and it's very simple to envision: permanent magnet field "pushes" free electrons contained in stator windings via their static electric fields. Here you have 2 potentials on windings: "-" and "+" since directionality of "push" is given.

But I absolutely fail to see the directionality of carbon rod's "push". It seems like it goes along the carbon rod and induces "push" along toroid's windings. So, it may have a directionality as well, but it's different from rotor generator. The good thing is that it should also have "+" and "-" on terminals (with beta it would be "-" on all terminals due to excess of electrons). One more vote for magnetic field amplification. ;)

Still, there is some problem with directionality of magnetic field "push": I still see how a gradually amplified magnetic field pushes electrons in all directions thus producing a rather vague potential difference. Well, maybe its much simpler. Carbon rod is an inductor with nobody-knows what kind of mechanism of magnetic field amplification. This inductor induces current in a toroidal windings. So, this can be easily simulated by changing carbon rod with an inductance and running some AC though this inductance and seeing what is collected on the toroid. It is a rather non-conventional transformer - that's why I cannot clearly see its function.

Feynman

@aleks
yeah i actually agree here, i think a fair part of this is flux amplification.

@all
I really think if its beta, most of it is contained to the rod and recaptured as flux.  Think about it... if a beta particle is emitted in the center of the rod, there is no way it will travel all the way out unless it is very energetic. It will be recaptured before exiting or else will lose significant kinetic energy on the way out as it scatters .

I'm going to go out on a limb here and make some predictions that may turn out to be way off.

Here why I think we aren't seeing ridiculous sunburns from these highly energetic little charged monsters:

(1) Some percentage of the beta turns to flux. I don't know how much. Let's say 50%.
(2) The vast majority of the remaining beta (49%) is emitted as relatively low energy rays (KeV or less), because it knocked into things on the way out of the rod and lost kinetic energy through scattering in the carbon.
(3) The remaining 1% of the beta are higher energy MeV rays, or whatever energy we are expecting from K-capture.  But these will only occur be produced on or near the surface, which is why they only account for 1/100 beta electrons. 


Now If this general theory is true, we can make some predictions about how the experiment will turn out. 
A) We should at least be able to detect some of the scattered beta rays using photo paper, and certainly if we scale the energy to 100-300V , 80,000uF.  We expect to see them in photo paper because the ionization energy of silver in photo paper is very low (eV).

B) Because of the scattering, we expect a broad spectrum of energies. So a few particles will be going very fast, there will be a median, and then there will be a few stragglers.  The prediction is that we can see at least a couple of different velocities.

C) The photo paper will show black dotted curves and lines on a white background in the presence of beta rays.

caveats:  If the ionization energy of the photo paper (for whatever reason) is higher than the rays, then we will see nothing.  BUT the photo paper exposes to light, so these would be some unbelievably crappy beta rays not to ionize the paper.  In fact, if we do not see them at the higher discharge energies, they are probably not there at all (or else there is a major flaw in the experimental assumptions or procedure).

Now the null hypothesis here is that the paper will remain white or uniformly grey if there is no beta.  No lines or particles, just uniform exposure or lack therof.  This is what engineer groundloop thinks (no beta).  There is a list on the previous thread page of what everyone thought we would get.

So the experiment should give is a rough idea of how much , if any beta, as well as its energy distribution.  Of course, if I get a bunch of plain white sheets of paper, that means tentatively, NO BETA.   Then, being as dedicated as I am to this cause,  I will double check by scaling the capacitor bank way past the existing 1100uF , to say, 80,000uF (the level of Juan and Naudin).  If i see nothing at 200-300V, 80,000uF , then we must be looking groundloops' EMF effect as Fester's OU mechanism.

Either way is okay with me, it's just the 'not proving' how Fester is getting the OU which is causing the problems here.  So this experiment will show us one way (BETA) or the other (MAGNETIC), or more likely, a little bit of both.

aleks

Quote from: Feynman on May 22, 2008, 05:38:00 PMif a beta particle is emitted in the center of the rod, there is no way it will travel all the way out unless it is very energetic. It will be recaptured before exiting or else will lose significant kinetic energy on the way out as it scatters.
Here is problem. Kinetic energy cannot be just "lost". You are going to see melting of the whole system considering 60kW/h of produced kinetic energy converted into heat.

At the same time magnetic fields make it possible to have 60kW potential without even seeing it's all there, because varying magnetic field does not have any effect on unclosed circuits: it does not induce dangerous voltage over them (electrons simply cannot be pushed - a closed path is needed for that - they are blocked by air). I think it's time to review the whole story and treat beta as approval this thing works, but not as a driving force behind this thing.