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Overunity Machines Forum



Energy from the Ground - Self powered generator by Barbosa and Leal

Started by hanon, August 13, 2013, 08:01:16 PM

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0 Members and 22 Guests are viewing this topic.

nelsonrochaa

Best regards,
These are the tests with ac network.
So far the best results are obtained.
I recall that the intent of these tests are not cheating or putting people in danger but to promote answers questions about the functioning of captor.Os results are not considered reliable because the magnetic field influences the readings.
But I will continue to study the results of further tests.
My interest has always gone to use the equipment outside the network electrica.Não there any legal issue with justice ... I suppose :)
Good vibes for everyone.

https://www.youtube.com/watch?v=czdXl2FJ8_8

Dave45

Nelson can you give us a schematic of your setup.
Thanks
dave

nelsonrochaa

Hi dave i reproduce the circuit based in patent.
This is only a transformer and i think is just a based joule ring circuit.If you see the video test with dc you see clearly that little magnet when activate the reed switch and pulse the dc 12v e acts like a joule thief.
The loop secondary is made with 3 cables stranded (I don't have lots of resources) i think it can change the result because e acts like a bifilar coil like other energy devices like kapanadze etc.
See and reed very well the patent because the small details make a lot off difference :)
I will out the weekend and rest with my family . soon i will continue , and wait other tests because my resources are low to make lots of different tests.I pretend to buy a ups or a inverter to make other tests :) i cant wait.
greetings   

nelsonrochaa

Good afternoon, I found that the circuit generates large amounts of reactive power  when an inductive device is connected.
My watt meter measures the power factor and noticed that when I connect an inductive load directly to the power grid power factor varies depending on the equipment but always below 1 always 0.75 to 0.79. When I turn on the same charge through the circuit power factor is always 1 which tells us that the efficiency of the equipment is the best, all the energy supplied by the source is consumed by the load and reactive power is not needed.
  but when I disconnect the capacitor from the circuit (output) power factor goes to 0.1, 03 ranging.
For example, to get 1 kW of real power when the power factor is unity (equal to 1), 1 kVA of apparent power will necessarily be transferred (1 kW ÷ 1 kVA = 1). Under low values ​​of power factor, to transfer a greater amount of apparent power to obtain the same active power is required. To get 1 kW active power with power factor 0.2 will need to transfer 5 kVA of apparent power (1 kW = kVA 5 × 0.2).
Apparent power is the product of the current and voltage of the circuit. Due to energy stored in the load and returned to the source, or due to a non-linear load that distorts the wave shape of the current drawn from the source, the apparent power will be greater than the real power. A negative power factor occurs when the device which is normally the load generates power which then flows back towards the device which is normally considered the generator.
When power factor is equal to 0, the energy flow is entirely reactive.
I think this matter is a starting point to understand some details of circuit operation.
I think the reactive power generated is stored in the condenser and fed to the load causing not consume active power in phase.
I think this matter is a starting point to understand some details of circuit operation.
I think the reactive power generated is stored in the condenser and fed to the load causing not consume active power in phase so the meeter dont count real power W.

Capacitive loads such as capacitor banks or buried electrical cables produce reactive power with advanced power compared with voltage. Both types of load absorb energy during part of the AC cycle, only to return back to the energy source for the remainder of the cycle.

sorry for my english :) some the notes a copy from wiki to explain this.
I would greatly appreciate your opinions, soon I will make a video to illustrate this explanation.
May also see some tests I published some time about inductive reactive energy with my youtube channel that can be useful loads.
Thank you


nelsonrochaa

One note :
In Portugal only the industrial market pay reactive power not the domestic consumer.
I say that because in this tests you create a great reactive power and if your provider charges you ...;) €$
bye