The Holographic Universe and Pi = 4 in Kinematics!

[Pirate88179]

Failure to distinguish between abstract geometric circles and physical circles led to the Explorer 1 anomaly.
"The launch of Explorer 1 in 1958, presided over by none other than Werner von Braun, provided an orbit that was more than 1/3 higher than expected. The orbit was so much larger that the rocket was at first thought to be lost. The expected signal was late, not by a few seconds, but by 12 minutes. Later that decade, Explorers 3 and 4 confirmed the anomaly, as did the three navy rockets of the Vanguard program."

If you read about Von Braun, and claim to know anything about orbital mechanics, you would know that a higher orbit is caused by a higher velocity.  This is basic orbital mechanics 101.  So, all that happened was that the vehicle that carried Explorer 1 went a bit faster than required.  They engineered in a fudge factor to ensure that it made orbit.  Orbital velocity is 17,500 mph and if you were in charge of that mission, you too would have added a bit more juice to make sure it exceeded that velocity.  If you erred on the slower side, no orbit would have been achieved.  The higher the orbit, the faster the vehicle needs to go.

Read some books on the first rendezvous and the math required to pull that off.  The craft at the lower orbit had to speed up to meet the other craft even though the other craft was behind it.  You had to slow down to speed up and/or speed up to slow down.

Bill

[gravityblock]

Straw man:  No one has stated that that "all distance has to be measured by a flexible string.

Placing a square around the circle and using the perimeter of the square as a base to measure the distance instead of a flexible string gives Pi = 4.  A perimeter is defined as the length of an enclosing curve.  Also, a perfect circle will be inscribed within, by rotating the surrounding square 1/4.  This example is known as Taxicab geometry or rectilinear distance.

Gravock

[TinselKoala]

If you read about Von Braun, and claim to know anything about orbital mechanics, you would know that a higher orbit is caused by a higher velocity.  This is basic orbital mechanics 101.  So, all that happened was that the vehicle that carried Explorer 1 went a bit faster than required.  They engineered in a fudge factor to ensure that it made orbit.  Orbital velocity is 17,500 mph and if you were in charge of that mission, you too would have added a bit more juice to make sure it exceeded that velocity.  If you erred on the slower side, no orbit would have been achieved.  The higher the orbit, the faster the vehicle needs to go.

Read some books on the first rendezvous and the math required to pull that off.  The craft at the lower orbit had to speed up to meet the other craft even though the other craft was behind it.  You had to slow down to speed up and/or speed up to slow down.

Bill

Nope. Higher orbits require _less_ velocity than lower orbits. To orbit lower, you must speed up, not slow down.

http://en.wikipedia.org/wiki/Orbital_speed

[TinselKoala]

Placing a square around the circle and using the perimeter of the square as a base to measure the distance instead of a flexible string gives Pi = 4.  A perimeter is defined as the length of an enclosing curve.  Also, a perfect circle will be inscribed within, by rotating the surrounding square 1/4.  This example is known as Taxicab geometry or rectilinear distance.

Gravock

It's known as "taxicab geometry" because taxis are confined to streets, usually, and can only travel rectilinearly. Also, it's a guess but probably true that many taxicab drivers have not been exposed to two years of calculus study and problem solving in institutes of higher education.
This does NOT mean that "pi=4", since pi is not defined that way in the first place, and I think you are just being silly.

[MarkE]

Placing a square around the circle and using the perimeter of the square as a base to measure the distance instead of a flexible string gives Pi = 4.  A perimeter is defined as the length of an enclosing curve.  Also, a perfect circle will be inscribed within, by rotating the surrounding square 1/4.  This example is known as Taxicab geometry or rectilinear distance.

Gravock

Only if the work is done wrong does it come out to four.  Only at the eight points on the circumference that lie on arcs that are multiples of pi/4 radians are the the insets from the inscribed box equidistant in X and in Y.  In all other locations the distances are unequal, invalidating the premise that the perimeter length of each successive approximation remains the same as that of the original inscribed square.