DaS Energy Overunity ?

[Kator01]

Wattlow Heating America, quote. Hoover Dam, quote. CO2 gas Industry, quote.

Refrigeration by similar means, Coles Supermarket.

...educate youself and do not quote misunderstood pieces of writings of these above companies.

You are stealing our time..

How about show us the respective Links to these quotes instead ?

Kator01

[LibreEnergia]

Wattlow Heating America, quote. Hoover Dam, quote. CO2 gas Industry, quote.

Refrigeration by similar means, Coles Supermarket.

So what you are attempting to tell us is that every physics and chemistry text book in the entire world is wrong?

I remember measuring this value in a high school  experiment. You can do it too. Take an electric kettle of known output (typically they are around 2000 watts) and measure how long it takes to boil a litre.

[TinselKoala]

Watlow is a big company with lots of products and lots of information on the internet. It should be easy for DaS to provide a link to this miracle water heater they are carefully hiding amongst all their sales info.

https://www.watlow.com/downloads/en/catalogs/cartridge.pdf

Using the tables for heating water in this
https://www.watlow.com/reference/files/wattage.pdf
and converting to metric/SI, we have 1.9 kW to heat 5 gallons of water by 140 degrees F (from room temperature to boiling, so less than 100 C rise).
So that's 19 liters of water raised by about 75  degrees C in one hour, this takes 1.9 kW applied constantly for the hour.
So if you did it in one second instead, this would need 1.9  kW x 60 secs/min x 60 mins/hour = 6840 kW for one second. But that's for 19 liters. One liter would thus require 6840/19 = 360 kW applied for that one second. But that's just for 75 degrees rise. So for 100 degrees rise we have 360 x 100/75 = 480 kW for one second.

This is in very good agreement with the calculation from the definition of the calorie (4.19 Joules per gram per degree C.)

ETA: I see they even give a nice equation for heating flowing water:

kW = Liters/min. x Temperature Rise (°C) x 0.076

So using that we find that raising one liter per minute by 100 degrees C takes 7.6 kW. One liter per second will thus take 7.6 kW x 60 secs/min = 456 kW.

[DaS Energy]

So what you are attempting to tell us is that every physics and chemistry text book in the entire world is wrong?

I remember measuring this value in a high school  experiment. You can do it too. Take an electric kettle of known output (typically they are around 2000 watts) and measure how long it takes to boil a litre.

Wattlow Heating America, quote. Hoover Dam, quote. CO2 gas Industry, quote.

[DaS Energy]

Wattlow Heating America, quote. Hoover Dam, quote. CO2 gas Industry, quote.

Hello Tinsel Koala,

Wattlow Heating do provide Kw heating for different fluids. The 0.076 1*C a litre of flowing water in one second is a quote, using a tank heater.