Partnered Output Coils - Free Energy

[tinman]

  I have written an entire article with diagrams about that issue here.  -  click on the blue links in that article to see more diagrams.

Here are some things to remember:
1)  (E=Li²)
2) The power of the final electric current flowing through a coil, does not represent the energy transferred to that coil's magnetic field.
3) Average current * Average voltage <> Average power
4) Power is not energy
5) Current is not energy
6) Voltage is not energy

(according to i²R)

P.S.
When I write that something is not energy, I do not mean that it is not a factor in an energy equation.

The final current flowing through a coil, does not represent the energy that was transferred to that coil's magnetic field

And this relate to my experiment how?. Dose the PM's field change the way current flows through a coil when that coil is an air core electromagnet?.

You are making a conceptual mistake by ignoring the time that it takes to reach this level of current.

Time is not a factor in the test,as it is an applied DC current,and this current may be applied to the coil for as long as you like.The point of the test is to show the force applied against the spring with a set amount of power/electrical energy,what ever you like to call it on the day, flowing into the coil.

Q: So what does the final current flowing through a coil represent?
A: It represents the power of the heater formed by the coil's resistance

So it takes no power to create the magnetic field around the coil?
If it dose,then that should be added to your above answer.

[Spilled Fluids]

Just as i thought,you have no answer,and thus you hide behind babble.
I have shown you how a PM increases the work that can be done with a set amount of power.
No other material you can come up with will increase the work being done against that spring with a set amount of power as show in my simple experiment.

Like all other self acclaimed guru's,you fail at providing a simple answer,and the reason is-you have none.The electrical power remains the same,and yet the work done against the spring is increased simply by adding a PM into the system. You deny the outcome,and yet you have no argument against it.

The only babble here is coming from you and your bent thinking.

You can't show me an experiment that does not use some outside energy input to get a PM to do work so you launch off on another one of your diatribes.
I gave you a chance to redeem yourself but you came up with an epic fail.

[tinman]

The energy to make the parts does not enter into the equation.  But the energy to put the pieces in place does, which for the ferrite is virtually zero.Yes it is small.That is correct.  The energy to make the magnet is not a factor.  There is some energy exchange moving the magnet into place.

If the ferrite keeper and the PM's mass is the same,and they have to be moved the same distance to be put in place,then the energy required to do so is the same in both cases.

[Spilled Fluids]

Ok,lets do it ass about.
We want to achieve say a 10 Lb pull force on that spring. With the ferrite block in place,we may need say 12v @ 2 amp's applied to our electromagnet to achieve such a force. We then replace that ferrite block with a PM of the same size,and we now find that we need only apply say 6V @ 1 amp to achieve the same pull force on that spring. So the work done against the spring is the same,but we need only apply half the energy to that electromagnet to achieve the same work done.

Exactly, the electromagnet is doing the work not the PM, not the ferrite and nor would a plain iron bolt...or are you going to try telling us that a plain iron bolt can do work?

[tinman]

The only babble here is coming from you and your bent thinking.

You can't show me an experiment that does not use some outside energy input to get a PM to do work so you launch off on another one of your diatribes.
I gave you a chance to redeem yourself but you came up with an epic fail.

Dear mister !my rocks wont bounce!
I gave you an experiment to carry out that shows a PM doing useful work. It dosnt matter what situation that PM dose that work in,weather it is additive to an existing force or not.
You(like all others so far) have failed to prove me wrong,and in stead,you hide behind irrelevant excuses. It dose not matter how that PM dose the work,nor dose it matter in what situation it dose it-->the fact is,it dose useful work. Now stop hiding,and explain as to how it is not doing useful work in the experiment i gave you-->you are yet to answer.