Zero and Q device

[v8karlo]

Hi Carroll. Yes, that all sounds correct to me. C1, C2, C3, Czero, and L1 are forming a voltage divider.
The (average) voltage across L1 therefore is not high enough to light up L1, except maybe just a little bit,
even though current is flowing through the bulb to charge up the capacitors. 

If voltage on L1 is so low, try to grab L1 with your hand.

Everything will be clear to you in split second.
L1 is directly on mains 220V.

But it can not push lot of current through bulb.
And in the second phase voltage is double on that line.

[v8karlo]

We can search for 1000 reasons why it won't work,
or why it can't work.


You have to build it only once in 1 hour.


We are talking here like we are going to build shuttle.
Any other scheme on this forum has more components than this.

[lancaIV]

Hi Carroll. Yes, that all sounds correct to me. C1, C2, C3, Czero, and L1 are forming a voltage divider.
The (average) voltage across L1 therefore is not high enough to light up L1, except maybe just a little bit,
even though current is flowing through the bulb to charge up the capacitors. 

Warning to potential experimenters:
Build at your own risk.
The 'zero device' circuit is actually not a very safe circuit to experiment with when connecting to the mains
or the output of an inverter. Not only could someone get a lethal zap from that circuit if they touch the wrong thing,
but if they connect a scope probe ground lead to the hot side (phase) of the AC line, they will short the hot phase to ground
(big arc, blown fuse or breaker) since the ground on a scope is typically not isolated from the mains ground.

http://web.archive.org/web/20040610181420/http://www.theverylastpageoftheinternet.com:80/menu/main.htm

http://web.archive.org/web/20040606131649/http://theverylastpageoftheinternet.com:80/forsale/plans/earthbattery/ebpage1.htm
http://web.archive.org/web/20040617011947/http://theverylastpageoftheinternet.com:80/forsale/plans/earthbattery/ebpage8.htm

super-low or super-fast Ohm conductor
Physics law and order modelling : the conditioning
https://translate.google.com/translate?hl=de&sl=de&tl=en&u=https%3A%2F%2Fde.m.wikipedia.org%2Fwiki%2FOhmsches_Gesetz
  a. not- b. steady , temperature, .......
     ..... EINZIG DIE KONSTANZ .... IST DIE KERNAUSSAGE DES OHMSCHEN GESETZES.
 
freI nach Stein : DIE KONSTANZ IST DIE KONSTANZ IST DIE KONSTANZ ( und nicht immer am Bodensee)

constant up and constant down, constant up and sharp down, sharp up and sharp down = Dirac surges

                    macro-/ nano-scale : friction/ Reibung, material delay actio/reactio time 
                                             

[Hoppy]

 My explanation for the operation of the 'Zero' circuit: -

Using my 25W bulb having a cold resistance of 204R, the bulb in series with a 10uf cap and diode, the bulb does not visibly flash on connection to a 240V mains supply. However, it will flash with a 20uf or higher value cap. The difference is due to the reactance of the capacitor allowing sufficient current to heat the bulb filament to a glow in the case of the 10uf cap. The combined series capacitance of C1 to C4 in the zero circuit is around 5uf, thus no flash.

When the transistor is switched 'ON' and conducts on one phase of the mains supply, caps 1 to 3 effectively discharge in parallel to a much lower resistance output circuit, via steering diodes, to common output rails to which L2 is connected. The combined currents through the lower resistance, discharged from caps 1 to 3 are sufficient to heat the filament of L2. However, L1 cannot light on this phase as the diodes in series with the caps are reverse biased. The caps are now discharged ready for re-charge on the next phase when the transistor is switched 'OFF'.

Altering the power rating of the bulbs and cap values will alter the impedance of the input loop to an extent whereby LI may be seen to glow together with L2.

[v8karlo]

My explanation for the operation of the 'Zero' circuit: -

Using my 25W bulb having a cold resistance of 204R, the bulb in series with a 10uf cap and diode, the bulb does not visibly flash on connection to a 240V mains supply. However, it will flash with a 20uf or higher value cap. The difference is due to the reactance of the capacitor allowing sufficient current to heat the bulb filament to a glow in the case of the 10uf cap. The combined series capacitance of C1 to C4 in the zero circuit is around 5uf, thus no flash.

When the transistor is switched 'ON' and conducts on one phase of the mains supply, caps 1 to 3 effectively discharge in parallel to a much lower resistance output circuit, via steering diodes, to common output rails to which L2 is connected. The combined currents through the lower resistance, discharged from caps 1 to 3 are sufficient to heat the filament of L2. However, L1 cannot light on this phase as the diodes in series with the caps are reverse biased. The caps are now discharged ready for re-charge on the next phase when the transistor is switched 'OFF'.

Altering the power rating of the bulbs and cap values will alter the impedance of the input loop to an extent whereby LI may be seen to glow together with L2.

It is very scientifically said.

Can not see any errors here.

And when grid line comes in serial with CZero it raises that line voltage to 525V, which explain 175V on each cap, C1, C2 and C3.
I also tried with 640uF caps and 2 x 150uF (minus to minus). Combined capacitance is little bit more in that case (3 x 640uF + (150uF / 2)) / 4 and effect was same as when I used 22uF. With bigger caps I was creating only bigger buffer. That means when I plug off the L2 continues to light for a second or two.

You are right Hoopy, it sounds ok to me!


The L1 flash for a moment at the beginning while C1, C2 and C3 are filling up. When they are filled L1 diminish and L2 starts to glow.
That means that C1, C2 and C3 must not be emptied all the way. Effect vanish. That is why resistance of load comes to play.At the beginning if the C1, C2 and C3 are bigger L1 will flash longer. It needs more time for caps to fill up.The L1 will flash only when all caps are emptied and then device plugged into grid.

It is best to build it and then observe it.
The fact is that L1 does not glow and L2 glows with heat.
Can you use this principle, adopt it with some other circuit or develop further?