Re: Self Looped Cap Dump Bedini Motor

[Dave Wing]

Hi Dave,

You say "Bloch wall", in above quote (my bold). I suspect you learned this from those books and vids. It is totally BS. I've been telling this to those folks on the Energetic forum for years. Finally I found an excellent reference to back me up. Please watch this video. She gets into the Bloch wall about 12:50 time marker.
https://youtu.be/vTV1EVb-V2c?si=sGgR95oeLOE2U7Vj

And the middle of the magnet (on axis between poles) does not repel iron. It may appear to, but that's because it is an area of little to no attraction and the nearby poles exhibit strong attraction. Easily seen with iron filings.
bi

Hey bi, I watched the vid when you posted it on Energetic forum. I'll post an image below by John Bedini... it shows what we are discussing here. Repulsion is real... the magnet does not attract the iron, which is opposite of the attraction a north or South Pole face.

John showed the loops north and south as you stated, see the bottom left corner image.

Dave Wing

[bistander]

Hi Dave,
People believe what (whom) they want. Good luck.
bi

[partzman]

FWIW, here is a copy of a post I made years ago on OUR on a private thread-

For any that might be interested, this is an improved design of coil/core used in tangential induction.  The idea is to have as large an area in one polarity as compared to the opposite polarity in a coil's current that has been induced with a tangential PM field.

The pix below is the PM and coil assembly used for this test.  The elongated core is 7 pieces of 1/4 ferrite E cores with 30 turns of 15-34 litz wire and the PM was moved past the core by hand.

The first scope pix shows an area of 2.975mAs for the total current waveform.

The second scope pix show an area of 4.265mAs for the positive area of the waveform.

From this we can calculate the negative area from 2.975mAs-4.265mAs = -1.29mAs.  Therefore, the positive to negative ratio is [4.265]/[1.29] = 3.32:1 .

What good is this?  Well, by using a balancing magnetic or electromagnetic arrangement on a rotor that will null the Lenz effect from the positive PM induction in this case, a very low drag PM generator can be built which should produce OU.

Regards,
Pm

Edit: I temporarily removed this post because I thot I had included the wrong scope pix. 

[Dave Wing]

Hi Dave,
People believe what (whom) they want. Good luck.
bi

Yes I agree with your point.

John appears to be using Howard Johnson's depiction of corner spins of magnets... if Howard was wrong then it can be that the screen shot below is right. To me it does not matter, the waveform it produces is what matters and how we can use it.

Dave Wing

[Dave Wing]

FWIW, here is a copy of a post I made years ago on OUR on a private thread-

For any that might be interested, this is an improved design of coil/core used in tangential induction.  The idea is to have as large an area in one polarity as compared to the opposite polarity in a coil's current that has been induced with a tangential PM field.

The pix below is the PM and coil assembly used for this test.  The elongated core is 7 pieces of 1/4 ferrite E cores with 30 turns of 15-34 litz wire and the PM was moved past the core by hand.

The first scope pix shows an area of 2.975mAs for the total current waveform.

The second scope pix show an area of 4.265mAs for the positive area of the waveform.

From this we can calculate the negative area from 2.975mAs-4.265mAs = -1.29mAs.  Therefore, the positive to negative ratio is [4.265]/[1.29] = 3.32:1 .

What good is this?  Well, by using a balancing magnetic or electromagnetic arrangement on a rotor that will null the Lenz effect from the positive PM induction in this case, a very low drag PM generator can be built which should produce OU.

Regards,
Pm

Edit: I temporarily removed this post because I thot I had included the wrong scope pix.

partzman, thanks for sharing your research.

Dave Wing