new powerfull gravity turbine at perpetual motion

[shruggedatlas]

good day
and thanks for all
i will take care of all your recommandations

first let me ask a some questions:
1-  if we put 101 books each over other , every book = 1 kg ,
how much weight do the first book from bottom carry up = ?

2- if each book has 10cm then we have 1010 cm in high,
how much force we need to move one book up for 1010 cm at one second by any way of newton law =?

3- to make a perpetual motion ,
if we get the first book from the bottom out, then we have two actions 
    a- the 100 books will fall down for just 10 cm by  gravity power of 100 kg at less than one second
    b- we need less than 2 kg to move this free book up and put it on the top ( reconstruct the poiential power of 101 books).

What you are describing is a type of perpetually unbalanced system.  People have been trying to do this exact thing.  The reason it has not worked so far is there is no practical way to keep the heavy side (100 books) from balancing itself by coming over to the light side (1 book).  If you have a method of doing this, you are golden.  Can't wait to see what you have.

[wattsup]

The question is;

1) How much power will you consume to "pull" the book from under the weight of 100 books fast enough to make the others fall.

[hansvonlieven]

G'day all,

I think usama is thinking about this sort of device:



It has been around since at least the 1950's. No-one has got it to work yet

Hans von Lieven

[Mr.Entropy]

Hi Usama,

first let me ask a some questions:
1-  if we put 101 books each over other , every book = 1 kg ,
how much weight do the first book from bottom carry up = ?

2- if each book has 10cm then we have 1010 cm in high,
how much force we need to move one book up for 1010 cm at one second by any way of newton law =?

3- to make a perpetual motion ,
if we get the first book from the bottom out, then we have two actions 
    a- the 100 books will fall down for just 10 cm by  gravity power of 100 kg at less than one second
    b- we need less than 2 kg to move this free book up and put it on the top ( reconstruct the poiential power of 101 books).

The energy you get from the 100 1kg books falling 10cm is 100kg * 0.1m * 9.8 m/s2 = 98J.

The energy required to lift one book up 1000 cm is 1kg * 10m * 9.8 m/s2 = 98J.

Simple calculations like these show why these overbalanced wheel things never work on paper.  If they work in practice, it's because there's something about simple mechanics that we don't know.

Cheers,

Mr. Entropy

[hansvonlieven]

LOL entropy,

Well said :-)

Simple calculations like these show why these overbalanced wheel things never work on paper.  If they work in practice, it's because there's something about simple mechanics that we don't know.

Cheers,
Mr. Entropy

Hans von Lieven