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Overunity Machines Forum



Roll on the 20th June

Started by CLaNZeR, April 21, 2008, 11:41:56 AM

Previous topic - Next topic

0 Members and 157 Guests are viewing this topic.

BATMAN

BATMAN here WAKE UP ALL SMELL ANYTHING TO GET YOUR BRAINS WORKING.

ARE WE GOING TO GET A GRAVITY WHEEL ON THE DATE OF JUNE 20 2008????

THAT IS THE ONLY THING THAT WE ARE ALL HERE ON THIS WEBSIT FOR!!!!

CAN ANYONE GET THIS ??? ABOVE??

BATMAN MIGHT HAVE TO POST VIDS.........TIME TO GO.

purepower

Quote from: ramset on June 09, 2008, 07:13:50 PM
Pure power thank you your the best [I mean it] yes 25-1  more info to follow[ doing some experiments myself here and not scale full scale]   the hydro question  a 5knot flow  into a 10 ft funnel  with a 12 inch opening at the bottom 10 ft side facing the flow 1ft side down stream [exit]of the funnel how many GPH at the 12 inch opening and will depth effect psi [power of this]  Chet

Thank you for the compliment!

Slow down a second, Im not sure I follow your question. Please either draw a pic or answer the following for the funnel:

For volumetric flow calcs:

Diameter(entrance)=
Diameter(exit)=
Velocity(entrance)=
or* Velocity(exit)=
Height(funnel, entrance to exit)=


For pressure difference:

deltaPressure = (specific weight)*(height)
Specific weight of water= 62.4 lbf/ft3 = .036111 lbf/in3

(Note when using this formula: if your height is measured in inches, use .036111 and you result is in psi; if your height is measure in feet, use 62.4 and your result with be in lb/ft2, convert to psi by dividing by 144)

To answer your question, the depth will change the pressure as a liner function.


You also say "[power of this]." Are you running the water through a turbine? If so, calculating power from the turbine gets much more complicated and we will need more information. Changing the pressure at the entrance would change the power as long as the pressure at the exit were to remain constant. The most important factor, however, is the flow rate.

-PurePower










BATMAN

BATMAN here Dirt digger Thank You You win the prize.

My point was to get people TO think about  THE "T" WORD.

With out "T" you can forget about any POWER GOING TO YOUR CARS WHEELS

sorry but BATMAN has to go turn on the forge and finish a job......a 3foot 100lb. wheel

Have fun!!!!!


purepower

Quote from: dirt diggler on June 09, 2008, 07:14:37 PM
Batman,
HP isn't what we're after here it's TORQUE that we want.
all the horespower in the world doesn't help you if you don't have the torque to back it up ;D
to turn a 10000 watt genset, you need 15 horse, give or take, depending on generator type.

Sorry dirt digger, but this is simply not true.

Power (HP, Watt) is a function of torque (lb-ft, N-m) times angular velocity (RPM, radians/second).

Power=(torque)*(angular velocity)

So if we have "all the hosepower in the world," we can generate all the torque in the world with a simple gearbox. As we generate more torque, however, we lose velocity...

-PurePower

purepower

Quote from: BATMAN on June 09, 2008, 07:25:01 PM
BATMAN here WAKE UP ALL SMELL ANYTHING TO GET YOUR BRAINS WORKING.

ARE WE GOING TO GET A GRAVITY WHEEL ON THE DATE OF JUNE 20 2008????

THAT IS THE ONLY THING THAT WE ARE ALL HERE ON THIS WEBSIT FOR!!!!

CAN ANYONE GET THIS ??? ABOVE??

BATMAN MIGHT HAVE TO POST VIDS.........TIME TO GO.


To answer your question, I dont think so. The release date is for the lever, aka "Sword of God," not the wheel. As far as Archer is concerned, he feels he has given the world the wheel already.

But you say "videos?" Id like to see them!..

-PurePower