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Overunity Machines Forum



A Self-Charging Adams Motor

Started by lanenal, August 23, 2008, 10:05:29 AM

Previous topic - Next topic

0 Members and 2 Guests are viewing this topic.

nievesoliveras

Quote from: lanenal on September 02, 2008, 06:11:01 PM
Here is how to apply the self-charging circuit to John Bedini's Monopole Energizer (or the SSG), feedbacks and comments are welcome.

Cheers,

lanenal

Pardon my intromission on this thread, but I am looking for an answer to get feedback to the source battery. On the graphic shown here there is an apparent resistor between R2 and Q1. If it must be there, what is its value?

Jesus

gyulasun

Jesus,

I can only give an "educated guess" which is you could try first around  47 or 100 Ohm and see any bad or good effect.  It creates a negative feedback in the emmitter, so the higher its value the more it works against the approximate unity gain of Q1 (unity gain because of R1=R2 chosen).  Also it may give some (little) separation to the induced voltage in L2 with respect to the gate control voltage of M2. And do not be surprised if you find there is little or no any effect of the resistor so you may omit it as well and short circuit its place.  So start with a 47 Ohm.

Note the drawing error,  gate of M1 should go to the collector of Q1 and not tied to the positive rail at all. Also the polarity of the MOSFETs as I wrote last year above, it still sounds good to me...  :)
I hope member lanenal reappears here too.

rgds,  Gyula

nievesoliveras

Quote from: gyulasun on January 05, 2009, 06:55:19 PM
Jesus,

I can only give an "educated guess" which is you could try first around  47 or 100 Ohm and see any bad or good effect.  It creates a negative feedback in the emmitter, so the higher its value the more it works against the approximate unity gain of Q1 (unity gain because of R1=R2 chosen).  Also it may give some (little) separation to the induced voltage in L2 with respect to the gate control voltage of M2. And do not be surprised if you find there is little or no any effect of the resistor so you may omit it as well and short circuit its place.  So start with a 47 Ohm.

Note the drawing error,  gate of M1 should go to the collector of Q1 and not tied to the positive rail at all. Also the polarity of the MOSFETs as I wrote last year above, it still sounds good to me...  :)
I hope member lanenal reappears here too.

rgds,  Gyula

Thank you @gyulasun

Would you be so kind as to draw on the graphic included how to make the connections you recommend?
Also, Are the Mosfet numbers the correct polarity needed?

Jesus

gyulasun

Jesus,

I modified the schematic as I think it is correct from circuit theory point of view, of course I cannot say it is overunity because it utilizes the flayback pulse energy of the coils just like in the original Bedini circuit, the difference is the regained energy feeds the same source battery, not a separate one.  You may also think on the question of charging and discharging a battery at the same time but do not be discouraged: the rate of discharge of the battery should slow down by this feedback!
The type of the P-channel MOSFET I indicated has an 55V maximum breakdown voltage, you may try to search for heftier types, though the 100-150V types have got higher drain-source ON resistance.  If you do not operate the circuit without diodes D3 and D4, then the flyback pulse amplitude may not go harmfully high due to the continuos load from the battery.
Diode types are fast or ultrafast rectifiers like UF4001  (not 1N4001) to catch most of the flyback energy.

rgds,  Gyula

nievesoliveras

Quote from: gyulasun on January 06, 2009, 07:12:11 AM
Jesus,

I modified the schematic as I think it is correct from circuit theory point of view, of course I cannot say it is overunity because it utilizes the flayback pulse energy of the coils just like in the original Bedini circuit, the difference is the regained energy feeds the same source battery, not a separate one.  You may also think on the question of charging and discharging a battery at the same time but do not be discouraged: the rate of discharge of the battery should slow down by this feedback!
The type of the P-channel MOSFET I indicated has an 55V maximum breakdown voltage, you may try to search for heftier types, though the 100-150V types have got higher drain-source ON resistance.  If you do not operate the circuit without diodes D3 and D4, then the flyback pulse amplitude may not go harmfully high due to the continuos load from the battery.
Diode types are fast or ultrafast rectifiers like UF4001  (not 1N4001) to catch most of the flyback energy.

rgds,  Gyula

I am asking you permission to post this diagram as it is shown here on my thread as a reference of a possible selfrun circuit. Can I?

Jesus