Gravity Mill - any comments to this idea?

[hartiberlin]

At seawater level the shuttles air volume has  now doubled, cause:
P1 x V1 = P2 x V2

so it is now 3200 Liters !
Now we must release almost 2415 Liters from it, so it has got still less than 785,4 liters, so the 785,4 kg weight attached to it can pull it down completely...  Agreed so far ?

[hartiberlin]

Now we move down to 20 meters and the airvolume will compress even further, cause we are now at 3 bar air pressure inside the shuttle ballon, due to the outside water pressure and the volume of the balloon has reduced to around 261 liters only... Agreed so far ?

[tbird]

hi all,

just called Mr. Herring.  got his answering machine with a message from his wife.  i left message telling about this forum and my phone #.  hope he shows up.

tbird

[bastonia]

fyi - Just sent John an e-mail ... also inviting him to chat ...

[hartiberlin]

Okay, now we need to refill the shuttle balloon isobarly ( at the same pressure)
at 3bar with about additional 1310 Liters again so it has a total of a bit more than 1570,8 Liters,
so to be able to rise it against its own 785,4 Kg attached weight and also against the 1 Meter water colum
it has to push beyond seawater level, which is another 785,4 Kg weight.

You see this is a lot of energy we must apply for the pumping !
To pump these 1310 Liters at 3 bar we need alone 109 Watthours of energy to do this !

So, this way it does not work.
We really must use a smaller pipe diameter just directly above seawaterlevel
so there must be no water column weight to be overcome and the water must
then be  sprinkled into an upper bassin via the pressure from the buoyant force,
just like a fountain.

Then we also can reduce the attached weight to the shuttle and have to pump less
air down at the 10 or 20 meter deepth.