what happens with an electric field when it did work on a charge?

[Creativity]

nice so we go forward.When we see this already i bring a next clue.

Pointed tip metal electrode is introduced in the presence of the efield from positively charged capacitor plate.Efield strength exceeds work function for sharp electrode tip.It allows it to loose electrons that accelerate through the field emiting photons.
Tip gets negative charge by electric induction and it's attracted to the plate.Obviously electrons deliver work,but field stays unaffected

Electron spring,here u go.

[tinu]

So?
This is how electronic microscopes work and they still needed a power plug last time I’ve checked.
(I imagine they need it for charging the + plate then discharging the metal electrode(s), but wtf do I know?! )

Obviously electrons deliver work,but field stays unaffected

Wanna bet on it?

[Creativity]

haha  the thing is indeed if the electron hits the plate,then the plate looses charge and needs to be recharged.But two things.
I place an nonconduction insulation right before the plate,so electron never reaches the plate.Plate stays charged and keeps emiting efield.Second thing,sharp electrode is not a part of the capacitor,just a piece of metal brought not between the plates of the capacitor,but to the side of it.

In this case capacitor looses no charge,so no power needed once charged.

[Dave45]

So what happens if you build your plates shaped like a donut with a hole in the center and your dielectric the same, you would have a cavity that would bombard whatever was inserted with efield from all sides.
As it moved through the capacitor it would be subjected to +-+-+- would this break water or maybe a more stable form of water ice.

[sparks]

Those free electrons accelerating because of the dielectric field gradient can be caused to miss the anode entirely by using a magnetic field.  The target you choose should be of interest.