Fusionchip's Bedini Feedback to Source!!!

[Pirate88179]

@ Hoppy:

Thank you for your sincere and intelligent reply.  Actually, as I have stated on OUdot com many times, I don't really believe in OU.  Nature loves equilibrium and unity so, I think we have to be happy with that.  The fact that someone can run something at X input and get 2 X out of it just tells me that we don't really know where the other input is coming from, but, it is coming from somewhere.  This is just my opinion.

The main problem I see with actual replication on this, and other, sites is....lack of finances.  Heck, I just got another computer out of the dumpster at my apartment complex and I know there are things I can use out of it. (and I will)  Take the Joule thief topic for example.  I started that topic and have posted 19 videos on youtube on my work there.  I too have had folks that said....well I did not have the 3904 transistor so I used something else, and I did not have a ferrite toroid so I used something else, and I did not have the 1k resistor so I used a 2k resistor instead and.....your device does not work at all!!!!

This can be very frustrating to say the least.  And yes, wire size, transistors, capacitors, and all other components are all variables on this stuff.  My way of replicating is to build it exactly like someone else did and then....tweak a little here and there and hopefully get better results. (sometimes not)

Anyway, I can tell you and I are both on the same wavelength here so I will shut up now.  Thanks again for your very respectful and intelligent response to my post.

Bill

[Groundloop]

Hi,

Attached is my newest circuit drawing for my two coil pulse motor/charger.

I use one FGS 12V 7A GEL (drained) battery as a input. Battery voltage is 9,24V.
On the output I have a similar battery. This was also drained (10,5v) but has climbed
to 11,25 volt during the last couple of hours. My design goal was to try to mix some DC
current through the coil with the AC current in the coils. I have tried to measure
both the input current and the output current. My moving Iron meter shows no sign of input
current. (Although there must be some small current flowing.) The moving Iron meter shows
a very very very little output current. I do not know how big it is but I do know it is bigger
than the input current because the needle has moved a tiny bit upwards! You can draw
your own conclusions since you already know the output voltage to be bigger than the input voltage.
I'm NOT claiming any o/u yet because there is difficulties doing an accurate measurements when
the currents are very low.

Groundloop. 

[Groundloop]

Hi,

Here is my solid state variant. One battery connected.
If the battery is charging then o/u else not.

I can see the circuit is oscillating by a dim light in the Neon bulb.

Battery start voltage: 10,32V

Circuit drops the battery voltage to 10,28 when first connected.
Then battery gains 0,01 voltage approximately each 1/2 hour. (So far.)
Battery has gained voltage to 10,30 after 1 hour of running.

I will keep this circuit running and report back in some hours.

[EDIT-1] Circuit has been running for two hours now. Neon bulb still glowing dim. Battery voltage 10,32 Volt.
[EDIT-2] Circuit has been running for three hours now. Neon bulb still glowing dim. Battery voltage 10,32 Volt.
             Seems that the voltage increase is leveling out now. No gain in one hour.

Groundloop.

[robbie47]

@groundloop:
There is something about this circuit I don't understand.
Back EMF is caused by switching off the transistor after being on.
That causes the bottom of L2 to have high voltage.
That would mean current is pushed into the minus pole of the battery.
Which means discharging the battery after already being discharged while the transistor is switched on.
What is wrong with this analysis?

Note: assuming the red pole of the battery is the + pole

[Groundloop]

Hi robbie47,

I'm not sure I understand this circuit myself. :-)

The circuit IS oscillating. I can see that a high voltage is created that light the small 65
volt Neon bulb. The coils is connected so that when the transistor is conducting current
through L2 then the magnetic field hits L1 and brings the base low, thus shutting off the
transistor. Then the L1 flips around and triggering the transistor again. The diode chain will
drop the voltage input on the collector by approx. 5,4 volt. That way the single diode is free
to conduct current to the battery. This will happen because the current always goes the
path of low resistance. The circuit has back emf voltages of approx. 65 volt. Because of
the single diode the L2 coil can only push a charge into the battery by the negative terminal, I think?

If there is someone out there that have another explanation, please correct me. All I know is that
the oscillator is running and the battery has gained voltage. It MAY just be that the voltage pulses
eliminates sulfur buildup on the battery lead plates, thus we see a gain in voltage.

Close to 4 hours run and the battery voltage is: 10,33

Groundloop.