Buoyancy wheel inside two conditions.

[tbird]

hi Low-Q,

so there are 4 small disk geared to the main shaft that keeps everything relevant?

i'll have to think about that a bit.

tom

[tbird]

hi Low-Q,

does the wheel rotate 360 degrees?  if so, how do you keep the joints on one side only?

tom

[Low-Q]

hi Low-Q,

does the wheel rotate 360 degrees?  if so, how do you keep the joints on one side only?

tom

Let's say that all four joints are fixed to each rod. Each rod with its piston and the belonging cylinders are apart in depth of the picture but tilted 45 degrees from eachother - as you see it on the picture. So there is four separate pairs of pistons and cylinders. The torque close to the wheel are suppose to move the pistons by following the path of the joints.

In order to move the pistons upwards the joint is following the paths right side. This action need force as long the piston is going upwards because of water pressure and weight of the pistons. This force is gravity, but is perfectly, or close to perfectly, counterforced by the magnet configuration.

In the position around C-G there is no uward force provided by the magnets as the rotor magnets are tilted 90 degrees on the magnetic field from the stator magnets. In the particular magnet configuration it does not take energy to tilt the magnets from 0 degrees in A-E to 90 degrees in C-G. So in that last position the joints want to follow the path downwards, or counter clockwise, by gravity - just as I want.

When the joints continue to go counter clockwise, the downward forces from water and weight of pistons is gradually counterforced by upward lift from the magnet configuration. This doesnt require energy either as explained earlier. And remember, there is no sticky spot to fight against. The magnets does not provide work to the system at all. They are in place for counterforce gravity ONLY in the desired positions of the pistons - when they are suppose to lift water upwards. So there is no counterforce working clockwise on the joints in position A-E - not counter clockwise either. The buoyancy force of the bigger volume from E to A via D, C, and B, is the only force that is left to affect the wheel. So what is the result? More torque counter clockwise than clockwise.

I my theory at least.... I put in the picture again so it is easier to follow the explanation.

We should meet some place so it is easier to explane - where do you live? Send PM if interested

Br.

Vidar

[Low-Q]

hi

you have presented a design i have never seen before.  i suppose it is used elsewhere, but i have never taken anything apart that used it.  it will take me some time to imagine the different forces at different positions. 

just to be clear, the joint is attached to a guide (the small circle) and has to follow that path, right?  if so, it could go backwards if it wanted to?

you can continue in the thread or answer here, it's up to you.

tom

ps  are the pistons light enough to float or will they sink on their own?

That joint is free to move back and forth unless there is a one-way bearing in place.

I have now also seen the flaw I have been searching for in that particular design. When the pistons are in position D-G there is no torque at the point of the joint. However, both the poles is forced to the right in D-G. As the joint now is on the top og the path, it will be forced backwards rotation.
Further, the force is to the left for B-F, but the joint is now on the bottom of the path. I both cases the joints want to go in the oposite direction.

Case closed untill I try another twist on that design

br.

Vidar