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Overunity Machines Forum



Don Smith's Device #9

Started by Xaero_Vincent, October 27, 2009, 08:04:19 PM

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Xaero_Vincent

Quote from: innovation_station on October 30, 2009, 02:38:59 PM
i beleave your last statement to be untrue ...  first of 50 kw ...  lol  im sure he said 50 w in his video.....

second ... it is clear you have little understanding what this device actually does ...

and sir im not trying to cut you down please dont look at it like that .. ok

now the rotating disc wich is a record ...  is coated in a special material that will break a magnetic connection ...  verry much like a super conductor ...   upon reconnect he draws his power he turns off and on the magnetic flux flowing from the magnet ...

ist!

If you listen carefully he says this:

"Each one of those power source will do 50 watts... about 50 watts... I mean 50 kilowatts."

So with 8 coils, he's essentially claiming the total machine output is 400 kW from a 28 mW motor.

Paul-R is replicating this so we'll see what results he gets.

dankie

It seems all too good to be true .

Most likely you would fail if you simply built the device the way it is physically shown without being an MIT graduate in EE and knowing what to look for , thats IF his devices are real .

He claims his devices were replicated but I have not seen any proof or demonstrations so far .


Steven Dufresne

Quote from: Paul-R on October 30, 2009, 10:50:42 AM
quote author=Xaero_Vincent link=topic=8219.msg206575#msg206575 date=1256836690]
Perhaps the RPM of the rotor will determine the frequency of the current flowing throw the coils.
Yes, it will. And the main circuit components need, in my view, to resonate
at this frequency, this being adjustable with a speed control.

Resonance is everything.
[/quote]

@Xaero_Vincent,
To further clarify what Paul-R is saying (and forgive me if you already know this)...

Coils have a resistance to being energized, called inductive reactance (unit is ohms.) The formula for it is:
XL = 2 x pi x f x I
where pi is 3.14159, f is the frequency from the rotor speed, and I is the inductance of the coil.

Capacitors also have a resistance to being energized, called capacitive reactance (unit is ohms.) The formula for it is:
XR = 1 / (2 x pi x f x C)
where C is the capacitance.

It seems the coils are using pretty thick wire and with not a lot of turns so this seems to be your fixed starting point. So pick your magnets, your length of the coils, wire thickness and number of turns. Calculate coil inductance (unit is henries, H) as:
I = ur x 1.67 x 10^-6 x ([N^2 x A] / l)
where ur is the permeability of the core (??? what value of ur to use for a magnet ???, air is 1, iron core is 100), N is the number of turns, A is the area of the face of the coil (in square meters, A = pi x radius x radius), and l is the length of the coil (in meters.)

Next, pick a frequency, f. This is the RPM of the rotor multiplied by the number of holes (or metal sections between the holes, same number).

Plug the frequency, f, and your inductance, I, into the formula for XL and see what you get. This is the coils' resistance to being energized.

Now in the device 09 circuit it looks like the coils and the capacitor are in parallel. The way the work in this case is when the coils are being energized, the capacitors are denergizing (discharging) and vice versa. For this back and forth to work with the least amount of loss, you want the inductive reactance to be equal to the capacitive reactance. This is called resonance and it is how a typical crystal radio tunes in a specific frequency and minimizes all others. So you want XL = XR. We know XL from our last calculation above. Since,
XR = 1 / (2 x pi x f x C), and XL = XR
we want to solve for C, the capacitance, so we rearrange things and get,
C = 1 / (2 x pi x f x XL)
So now we know the capacitance of the capacitor we need to find/make.

So, yes the frequency is determined by the rotor speed, but the coils and caps have to be designed for or tunable to that frequency otherwise your losses will be tremendous. And after you've gone through the calculations you'll likely find you'll want to change your frequency to get a more reasonable capacitance.

Unknowns for me at least are what is the value of ur for the magnets and what is the effect on a permanent magnet core on a resonating coil?
-Steve
http://rimstar.org   http://wsminfo.org
PS. I highly recommend anyone whose never done the calculations to do them and see what values you get for inductance and capacitance and see how easy/hard it is to find/make components that have those values and then go back and adjust the calculations and so on. How many people build devices without knowing that they may not be working because of huge losses because they don't know how to calculate them?
PPS. I'm not an EE. I know this stuff because I learned from my mistakes. Now I pay attention to this stuff. Just trying to pass it on to others so we can all succeed.
He who smiles at lofty schemes, stems the tied of broken dreams. - Roger Hodgson

innovation_station

steve i do agree with you ...

and if it was 50kw/ coil wow...  but

i still seem to think you do not need all the resonant tuneing ... this thing can work in a much simpler operation..

the tuneing is needed to tune your coil ..  what i speek of is diffrent than dons device .. 

however they share some common things  the only tuneing required is to the PERMANT MAGNET  ;) :D

anyhow im gonna leave it alone ..  :)

ist!

i know his work is verry real ...  8) :P

do dons demo

THIS CONSISTED OF A TESLA COIL RUN FROM BATTERIES AND 2 INSOLATED STEEL PLATES OF THE SAME SIZE AND AN EARTH GROUND ...  THROW SOME LIGHT BULBS IN LINE ...  WATCH EM LIGHT UP FULL BRIGHT!  ;)

IF YOU WANT CHEEP SIMPLE PROOF OF MASSIVE AMOUNTS OF FREE ENGERY .. AS SOME CALL IT

TESLA CALLED THIS CONVERSION ..  ;)
To understand the action of the local condenser E in fig.2 let a single discharge be first considered. the discharge has 2 paths offered~~ one to the condenser E the other through the part L of the working circuit C. The part L  however  by virtue of its self induction  offers a strong opposition to such a sudden discharge  wile the condenser on the other hand offers no such opposition ......TESLA..

THE !STORE IS UP AND RUNNING ...  WE ARE TAKEING ORDERS ..  NOW ..   ISTEAM.CA   AND WE CAN AND WILL BUILD CUSTOM COILS ...  OF   LARGER  OUTPUT ...

CAN YOU SAY GOOD BYE TO YESTERDAY?!?!?!?!

Xaero_Vincent

Steven, thanks for the formulas. I can't remember formulas to save me.

This is all I can solve for inductance now since I don't know the length of the cable to solve l or A nor the permeability of the Neodymium magnet core with coils wrapped around a PVC pipe with an air gap in-between.

I = ur * 1.67 * .000001 ([100 * A] / l)

I can tell based on the light shining off the coils that there are 10 windings. The wire looks to be about 8 AWG?

One thing that makes the whole thing dis-believable is the math used here:

http://web.archive.org/web/20060516002624/www.altenergy-pro.com/device09-2.htm

8 coils, each producing 1000V @ 50A therefore equates to 8000V * 400A = 3.2 Megawatts? WTF? If the coils were connected in parallel then the amps would increase while the volts stayed the same and vice versa.

This leads me to believe that there were no accurate measurements done by Don. 1000V @ 50A might be possible but the number is too rounded and "on-the-dot". Why isn't it something like 982V @ 49A--something more believable than a perfect 50kW?


Regards,
Vincent