Newcomer to the overunity game, couple questions.

[mike-ao]

- don't trust those who say they have a working machine if they do not present obvious evidence and without having yourself duplicate their system.

especially, when someone replaces his background-noise with some musics in their video.

[mscoffman]

Mathematically the equation for energy is in units of WattHours
which has a time derivative.

WattHours is what your electric meter measures and what you
get billed for. Is was work done.

If you remove the time factor from the equation by saving "Watts
Continous" or "Watts Instantaneous" you remove the time derivative
from Energy and you have Power. WattsHours = Work. (having done it)
Watts = The Instataneous ability to do Work. (can/could do work)
A circuit formed from a bunch of wires has a maximum Power but
work is done only when those wires are used for a certain amount
of time, only then does the circuit have an Energy.

Power = Voltage * Amperes , and is measured in units of Watts.

Obviously Power is proportional to Voltage (at a constant Current).
but you can't assume the current is constant and generally will
need to measure that too.

:S:MarkSCoffman

[solinear]

@solinear,

Since you're trying to educate others, promptly correct the following nonsense regarding the meaning of "wattage" which you've said not once but twice:

You're probably right - I should have said the following:

"Don't *just* measure volts, measure your volts and combine it with amps to get watts, as watts are the only thing that matters."

I guess I've seen about 500 too many people going "OMG, I put in 2 volts and got 27 volts out, it must be overunity, I'm a genius!!!!!!" that I don't want to hear about volts any more.  Watts are universal - 500 watts worth of work is the same whether it's being done with 1.5 volts @ 333 amps, 12 volts @ 83 amps or 120 volts @ 8.3 amps.

BTW, don't forget that you can have voltage at 0 (or at least negligible) amps - it's called static electricity.

Edit: Oh yeah, if you're irritated at my definition of "Watts = actual work done", then you should redefine it and get universal agreement that 745 watts != 550 foot pounds/second of work.  Until then, watts are a measurement of work done over the course of a second.  All but one definition that I have found online has the word 'work' used as an integral part of the defining what a watt is, whether talking about electrical energy or mechanical energy.

[WilbyInebriated]

@solinear,

Since you're trying to educate others, promptly correct the following nonsense regarding the meaning of "wattage" which you've said not once but twice:

LOL. classic... at least he knows W = V x I.

and solinear, you don't 'combine' V and I... you multiply them. this is what you meant to say.
"Don't *just* measure volts, measure your volts and multiply it with amps to get watts, as watts are the only thing that matters."

[WilbyInebriated]

Edit: Oh yeah, if you're irritated at my definition of "Watts = actual work done", then you should redefine it and get universal agreement that 745 watts != 550 foot pounds/second of work.  Until then, watts are a measurement of work done over the course of a second.  All but one definition that I have found online has the word 'work' used as an integral part of the defining what a watt is, whether talking about electrical energy or mechanical energy.

dude, get a clue... from the wiki:

definition of joule:  "The work required to continuously produce one watt of power for one second; or one watt second (W·s) (compare kilowatt hour). This relationship can be used to define the watt."

you are confusing a watt with a one watt second...