Magnetic Engine

[vineet_kiran]

Interesting setup. I think the most tricky part is to synchronize the movement of the flywheel with that of the shielding plate. Btw. I guess the flywheel would lose energy while passing either by
1) the solid shield - holding the moving magnet back resulting in cogging
2) the repelling pole - which the moving magnet needs to overcome first before it profits from the "push"

I don't think it's possible to get at a point where the pole of one magnet is at a position where only a repulsion accelerating the moving magnet in the "right direction" will take place (so says the experience unfortunately).

@gauschor

Synchronization  can be achieved  easily  by using  a  90 degree cam.     Example  of such a cam is available  in the  following   website.       
http://www.technologystudent.com/cams/camdex.htm
When piston comes back  ( when moves towards  stationary magnet)   it will not experience  any force  because  the cam  lifts  the shield  which in turn absorbs  the  flux  of  stationary  magnet   eliminating  repulsion.         When   piston magnet  comes   close to the  stationary magnet,       the  shield falls   due to 90 degree  fall  in the cam   exposing   the  repulsive  face of the  stationary  magnet   which  suddenly  repels  piston  magnet  with huge force.

If  you build  the engine  based  on this design,  you may  have  to  attach  non-magnetic  weights  on the rear  sides  of  the shield   which  makes  it  to fall  at 90 degree position of the cam.       The  energy gained  by flywheel  during  repulsion will  be  enough  to  lift the  shield  slowly again,   when  piston magnet  moves  away  from the    stationary   magnet.
Synchronisation   can also  be achieved   by  connecting    the shield  to  a quick  return  mechanism.    In that  case  you need   not  use  weights   on the shield.

Regards

Vineet.K.
 

[vineet_kiran]

Yes, mass can be converted into energy, but that also means that mass is loosed. You can get energy out of a magnet, but that means the cost is to loose magnetism. What use do you have of a non magnetic magnet which has released all its potential energy into work?


Vidar

What  is the use of  Nuclear Power Stations in which  mass is lost?

[gauschor]

@vineet_kiran: ah thanks for the hint, now I understand the setup completely. Nevertheless I think the problem remains:
First: the flywheel will lose energy by the transmission of the axis using the cam.
Second: The cam needs a considerable force to move the plate because the plate needs a counterweight to be pushed down.
Third: The cam needs even more power because the shield will be attracted to the solid magnets trying to hold the shields to its pole
Fourth: You still won't be able to get a point where the shield is only pushing the moving magnet in its direction: why?
Either the shield moves down too early => then the moving magnet is facing the same pole and you need to overcome the force of the opposing magnet first, before gaining a "push" in the right direction
Or the shield moves down too late, in which case the moving magnet will lose energy because he is getting attracted to the shield

[Low-Q]

What  is the use of  Nuclear Power Stations in which  mass is lost?

Nuclear power stations is using the potential energy inside an unstable isotop. The energy will reduce the isotops mass, but remember that 1gram of mass is enough to power 1500 average housholds for one year (given that there is no loss). Litterally a grape that is converted to pure energy will power your house for 1500 years. Nuclear reactions is different from magnetism. Magnetism is a force, but nuclear reactions produce energy. Distinguish energy from force. Energy is a product that can do work. Force is not a product. Force alone cannot do work.

[vineet_kiran]

@vineet_kiran: ah thanks for the hint, now I understand the setup completely. Nevertheless I think the problem remains:
First: the flywheel will lose energy by the transmission of the axis using the cam.
Second: The cam needs a considerable force to move the plate because the plate needs a counterweight to be pushed down.
Third: The cam needs even more power because the shield will be attracted to the solid magnets trying to hold the shields to its pole
Fourth: You still won't be able to get a point where the shield is only pushing the moving magnet in its direction: why?
Either the shield moves down too early => then the moving magnet is facing the same pole and you need to overcome the force of the opposing magnet first, before gaining a "push" in the right direction
Or the shield moves down too late, in which case the moving magnet will lose energy because he is getting attracted to the shield

@gauschor,

All the above problems can be overcome by correctly timing,  machining of various parts, selecting correct thickness and weight of  the shield,  strength of magnets etc.

I conducted the above experiment by suspending the piston magnet like pendulam and allowed it to fall towards stationary magnet by gravity.   I  could move the shield without encountering  any of the problems you have stated above.   I  couldnot build a genuine model because I don't have proper machining / fabrication facilities.


Regards,

Vineet.K.