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Overunity Machines Forum



Quantum Energy Generator (QEG) Open Sourced (by HopeGirl)

Started by madddann, March 26, 2014, 09:42:27 PM

Previous topic - Next topic

0 Members and 110 Guests are viewing this topic.

MileHigh

Bill:

Yes just made it up.

PCB:

You are close, but you are just making an observation and not actually explaining, similar to F_Brown.

MileHigh

PCB

F_Brown 

I appreciate the work you have done in constructing this model and posting it here for others to work with it.  I was wondering what the dynamics of the primary tank circuit are in your sim?  Ariovaldo has posted some values for the primary in his build. Rotor frequency 235 Hz. High voltage primary coil ( 3100 turns of 20 awg wire) 33 Ohms, 13 Henry without rotor, 18 Henry with the rotor. Primary capacitance 0.16 uF. With these values the time constant for the primary would I guess be that of the inductor. t=L/R or about 0.54 secs.  Simon Derricutt calculated that at 7 KV peak-to-peak ( primary ac voltage)  that about 4 Joules of energy would build up in the circuit due to the capacitance in the circuit at resonance. What do your simulations show? So I estimate that it would take at least 2 secs to build up that amount of energy (4xt). After time t the amount of energy would be 4J * 0.63 or 2.52J

MH: Need to prepare my response to be-do  ;D

There is a great deal of focus on extracting power out of the primary using a "transverter". That is to harvest some of the stored energy in the primary tank circuit. The questions is how much energy could be extracted, while setting aside how this might be done.  At 235 Hz the cycle time is 0.0043s (not sure if I'm correctly taking into account  the number of poles here?)   Then one could only extract 2.52 * (1 -exp (-0.0043/0.54)) = 2.53J *0.00785 = 0.0198 or  0.02J per cycle and for it to be replenished. So total power that could be extracted and replenished because of the time constant of the inductor is 235 * 0.02J =  4.7 Watts. Whow! have I done this right??? Perhaps some folks here might also do the calculation its real late. 

MarkE

Quote from: MileHigh on June 13, 2014, 11:39:36 PM
PCB:

I see that you got a reply:

http://be-do.com/index.php/en/forum/qeg-general-topics/451-please-explain-what-does-var-mean

That sounds like Wayne Travis!  lol

Vgray35 speaks with a bifilar tongue.

MileHigh
Wow that quote was hilarious.  Someone might ask the poster if he realizes that Lenz' Law only determines direction.

F_Brown

Quote from: PCB on June 14, 2014, 01:05:08 AM
F_Brown 

I appreciate the work you have done in constructing this model and posting it here for others to work with it.  I was wondering what the dynamics of the primary tank circuit are in your sim?  Ariovaldo has posted some values for the primary in his build. Rotor frequency 235 Hz. High voltage primary coil ( 3100 turns of 20 awg wire) 33 Ohms, 13 Henry without rotor, 18 Henry with the rotor. Primary capacitance 0.16 uF. With these values the time constant for the primary would I guess be that of the inductor. t=L/R or about 0.54 secs.  Simon Derricutt calculated that at 7 KV peak-to-peak ( primary ac voltage)  that about 4 Joules of energy would build up in the circuit due to the capacitance in the circuit at resonance. What do your simulations show? So I estimate that it would take at least 2 secs to build up that amount of energy (4xt). After time t the amount of energy would be 4J * 0.63 or 2.52J

In this situation a simple measurement with a hand-held inductance meter at a single tiny current level is going to be of very little use because the inductance of the primary as well secondary vary greatly with current.  You have to go back in this thread I think around the pages in the 80's or so to find the graphs from my FEMM analysis data that shows the winding inductances vs rotor position and winding current.  I'm unsure of where I put them at the moment.

As for my SPICE model, it fails to indicate the inductance range explicitly on the schematic, because the inductance data is buried in the inductance lookup table, although if you run the model and display a trace of the H node you can see the dynamic value of the primary inductance in the circuit(see attached image)

Quote

MH: Need to prepare my response to be-do  ;D

There is a great deal of focus on extracting power out of the primary using a "transverter". That is to harvest some of the stored energy in the primary tank circuit. The questions is how much energy could be extracted, while setting aside how this might be done.  At 235 Hz the cycle time is 0.0043s (not sure if I'm correctly taking into account  the number of poles here?)   Then one could only extract 2.52 * (1 -exp (-0.0043/0.54)) = 2.53J *0.00785 = 0.0198 or  0.02J per cycle and for it to be replenished. So total power that could be extracted and replenished because of the time constant of the inductor is 235 * 0.02J =  4.7 Watts. Whow! have I done this right??? Perhaps some folks here might also do the calculation its real late.


I believe I found what may be a better way to get energy out of the QEG primary.  That is with an external step-down transformer with a parallel phase correction capacitor placed in series with the primary.  In this case the secondary on the QEG core can be omitted.  Also this method completely avoids having to deal with the funky variable coupling coefficient between the primary and secondary of the QEG.   In simulation this method is able to extract greater than 10kW of power from the primary of the QEG at up to about 70% efficiency. 

In the image here, the green trace is the inductance of the primary in henrys read on the voltage scale, the blue trace is the rotor position ramping repeated through 90 degrees rotation read on the voltage scale(this is because the FEMM analysis only generated data for 90 degrees of rotation and this works because of the symmetric and repetitive nature of the rest of the rotation), and the red trace is the current in the primary read on the amp scale after the system has stablized.

Looking at this myself, it's interesting to note that the primary inductance peaks when the rotor is best aligned with a pole.  The FEMM analysis showed that the primary inductance peaked when the rotor was best aligned with a pole and the primary current was at about 138mA.  This also seem to be close to the primary current in the simulation when the inductance is peaking in the image below.

Another interesting thing to note is that the current in the primary is rising when the inductance is falling.  Somebody previously mentioned in their analysis of variable inductance that in order for the energy in a circuit to be conserved during a decrease in the value of an inductor, the current in the circuit would have to increase, and vice-versa, with increasing here meaning moving away from zero for AC current.  The image below correlates well with that idea considering the inductor here is also part of a tank circuit.

Cisco

Quote from: Farmhand on June 13, 2014, 05:25:25 PM

They might as well go to Tesla's grave and spit on it, they do him a great injustice. And continue to do so. So it's like returning to spit on his grave every day. Despicable behavior.


This is similar to what Mylow actually did when he visited Howard Johnson's grave in mock reverence. Mylow had likewise claimed to have designed his phoney magnetic motor based on Howard Johnson's magnetic device and patent. Such drama! I gotta go, even my cat is barfing now.