Partnered Output Coils - Free Energy

[stivep]

Maybe he didn't like your "tone" in the comment or the post. You are yelling at him (using all caps and boldface) and have a generally argumentative attitude

O yes we should not be offended withFree Energy Overunity BULLSHIT! of Dave?
https://www.youtube.com/watch?v=hoqF3gjLIyI&google_comment_id=z133v1cy5nqqxdzuh22wzf2x0zuswjlmz
is that what you suggest?
he was first yelling louder using his voice and than block comments.
I have rights to not like him yelling at me.

I probably would have reacted the same way

Yes you are better than Dave.
And I respect you for that.
You would not answer- that is your decision
But you answering me,  and telling me  that  you would not answer
That is better than talking to someone who does not have balls to say that he will not answer.

In fact you just called some of us "morons" I think, and I resent that

.
please read carefully
I said

from Wesley:some moran's that accidentally read my post

.

that means  some that are not or possibly not interested  with understanding my true need to explain certain  subjects that I  touched here,
It is up to  individual to assign himself  that they fall into this category
Obviously you  decided that you are moran.
my explanation is
Not you not a Moran and I never meant that to you.
I name you my friend (* in red)TinselKoala

the same as  plenty of other gentleman 

he covers equipment from many sources and definitely does _not_ always give positive reviews.

Yes he got the most of negative  dislike marks of all of his videos, that did not  help him even
when  he  dumb my comment to trash so others can not see it.


What kind of scum would do that?
No gods to face his own words?
 
Now he made some  more videos and this one is not to much problems for him any longer


question for you is that fair?

But nobody needs to take Dave's word for anything, because he _shows_ what he is talking about and _demonstrates_ the validity of what he says. He made a couple of minor errors in the debunking video and you may not like his use of language... I don't like it much either, but I can choose to watch him,

You right
However being good in one thing does not make him valuable in universal  terms.
He must promote his business to make money on it. the same way as plumber or electrician does.They are also  good in what they do.

I promote no-one for money not  I care.
Do you see adds on my videos?
As long as YouTube  does not push me there would be  none.

you want to know my true nature?
this is me:

https://www.youtube.com/watch?v=l-Cvm_0XEjg

No harm to nobody!!!
Till someone    harms me.

Hey, I've got old analog equipment too. HP180a, that still works perfectly after all these years  My primary Function Generator is an Interstate F43 high-voltage FG that will do 40V p-p.  HP RF signal generator 8640B that I've restore

I respect that.]
No Rigol lived that long and first one that was a joke.
However it is good that now we have that choice too.
I was just pointing  right way in my opinion to make investment that gives you more money when you sale it  at the right time  and buy another one,
New will never sale for more  and never you will buy for price of good american made.
that is why new rigol cost as much as most 20 years old used Tektronix or Lecroy.

The Rigol DS1054Z will make a great and much needed addition

it certainly will.


Wesley

[Void]

Hey guys. See the attached scope screen shot for the input voltage and current waveforms
for an experimental transformer I have been testing with.
Input Voltage = CH1 = Yellow
Input Current Waveform = CH2 = Blue

As you can see in the scope screen shot, the input current is close to 180 degrees out of
phase with the input voltage. No, I don't have a scope probe connected backwards, that's the
actual input waveforms. I have tested to make sure the phase measurement is stable by
moving the scope probes and scope probe leads around, and the displayed phase shift remains stable.
This indicates that the phase measurement is probably not being significantly affected by fields from wires
and windings getting into the scope probe leads.

I logged data samples of the waveforms to a CSV file and calculated the average power using a spreadsheet.
Input power calculated out to -103uW. That of course doesn't seem likely, as the signal generator is
definitely supplying some current. Output power to the load (head to toe parallel LEDs) from the secondary winding
in my setup is approximately 1mW or maybe a bit less.

What does a 180 degree phase shift on the input current waveform indicate to you?
I am not taking these measurements at face value, as I know from many experiments that the
phase shift shown on a scope can be misleading sometimes, but, just in general, what does a 180 degree
phase shift between input voltage and current waveforms indicate? To me, I would think it indicates that all
power is reflecting back to the source. In radio terms, that would be like a very high SWR, where the reflected power
is about equal to the forward power. Or maybe a high SWR would have a 90 degree phase shift on the current? What do you think?
Take note I am not making any assumptions, especially in regards to over unity or anything else.
Just want to know how people would interpret such a 180 degree phase shift on the input waveforms
to the primary winding on a transformer.

P.S. Stivep, Chill out guy. The world has always been really screwed up, and no particular country
in this world holds a monopoly on being messed up in various ways.
All the best...

[MarkE]

Wesley

The new links work.  I watched that episode #708 several weeks ago.  Dave's critique of the poster's claims and associated YT video were done quite methodically.  I did not slog through the many comments of the original thread or that followed that episode of EEVBLOG.

[MarkE]

Hey guys. See the attached scope screen shot for the input voltage and current waveforms
for an experimental transformer I have been testing with.
Input Voltage = CH1 = Yellow
Input Current Waveform = CH2 = Blue

As you can see in the scope screen shot, the input current is close to 180 degrees out of
phase with the input voltage. No, I don't have a scope probe connected backwards, that's the
actual input waveforms. I have tested to make sure the phase measurement is stable by
moving the scope probes and scope probe leads around, and the displayed phase shift remains stable.
This indicates that the phase measurement is probably not being significantly affected by fields from wires
and windings getting into the scope probe leads.

I logged data samples of the waveforms to a CSV file and calculated the average power using a spreadsheet.
Input power calculated out to -103uW. That of course doesn't seem likely, as the signal generator is
definitely supplying some current. Output power to the load (head to toe parallel LEDs) from the secondary winding
in my setup is approximately 1mW or maybe a bit less.

What does a 180 degree phase shift on the input current waveform indicate to you?
I am not taking these measurements at face value, as I know from many experiments that the
phase shift shown on a scope can be misleading sometimes, but, just in general, what does a 180 degree
phase shift between input voltage and current waveforms indicate? To me, I would think it indicates that all
power is reflecting back to the source. In radio terms, that would be like a very high SWR, where the reflected power
is about equal to the forward power. Or maybe a high SWR would have a 90 degree phase shift on the current? What do you think?
Take note I am not making any assumptions, especially in regards to over unity or anything else.
Just want to know how people would interpret such a 180 degree phase shift on the input waveforms
to the primary winding on a transformer.

P.S. Stivep, Chill out guy. The world has always been really screwed up, and no particular country
in this world holds a monopoly on being messed up in various ways.
All the best...

Measured correctly, where voltage drop is taken across a branch and current is taken through that branch, then for: -90^o < phase shift < 90^o the branch dissipates power, and for: 90^o < phase shift < 270^o the branch supplies power.

[Void]

Measured correctly, where voltage drop is taken across a branch and current is taken through that branch, then for: -90^o < phase shift < 90^o the branch dissipates power, and for: 90^o < phase shift < 270^o the branch supplies power.

Hi MarkE. Right, this I do understand, but I would think a 180 phase shift on the current should not be possible with a passive circuit
(should not go beyond -90 to 90 degrees), hence my wondering how this can be. It seems it does imply that the passive circuit
is generating power, which, again, should not be. As far as connection of the probes and settings on the probes and scope,
everything checks out as being set correctly. I will continue investigating and see what I can figure out.
All the best...