Partnered Output Coils - Free Energy

[Dog-One]

So MH, can we assume Brad's measuring devices all have at least 3 significant digits of precision?

I would think that is a bare minimum for any such device.

[ayeaye]

Ok, i have here a 9V battery, VARTA, alkaline. I have a multimeter, Mastech MAS830B. Did cost some $15, something, not $5. Yet as i said, when 830 is in the name, the chip is the same as in $5 multimeters, which also have 830 in their name. Thus the digital precision should also be the same.

When i measure the battery in the 20V range, it shows 9.20 . When i measure it in the 200V range, it shows 9.1 . And if i measure it in the 600V range, it shows 8 . I tried it several times, all the time the results were exactly the same. So i would say, +-1 digit.

The voltage is though, 9.15 to 9.25 V, because the analog measurement error, 0.5%, is still greater.

I did it just now, really did it with a multimeter and a battery. I don't lie.

I guess i know where your thinking goes. Just in case, better to be sure. But this is not a proper thinking for research. With that thinking i guess, Faraday did dismiss his induction experiment results entirely. But he didn't.

[EMJunkie]

Consider the measurement of an AC voltage with a DMM indicating 1.48 volts.
Also consider the following accuracy spec for that DMM:

AC Voltage: (2V,20V,200V) ± (0.8%rdg+3dgt),750V(1.2% rdg+3dgt)

Now, work out the range of possible values that measurement indicates.

A displayed value of 1.48 VAC indicates that the measured voltage is actually any value between 1.43 to 1.52 volts.  Because of this, little weight can be given to that last digit.

Even adding an additional digit to the meter while keeping the accuracy specs the same would only result in reducing the possible range of the measured voltage to between 1.465 and 1.494 volts.

Also note that many DMM specs typically incorporate the instrument's frequency response into the AC measurement specs that must also be given consideration.


I do not consider 8 bit digital scopes all that accurate.  Just as there are DMM's available with increased resolution and accuracy, there are digital scopes available with greater resolution and accuracy as well.  As far as automated functions go, they typically have nothing to do with accuracy and are more so merely a convenience, just as a cruise control and electric windows offer little in the way of performance to a car.

Actually, 269.2 amps and 362.3 watts...

Its not the math that is the problem (when properly applied), it is about the accuracy of the numbers acquired and plugged into that math.  Possibly you utilized a 6 digit meter of known calibration and its 4 wire resistance measurement mode to determine with a good degree of confidence that you actually have exactly 1.436 volts and a .005 ohm resistor.  Otherwise, as they say, its garbage in garbage out.  All measuring instruments provide measured values as a range of values determined by its resolution and the accuracy specs provided.  Any calculations made using those measured values must also result in a range of calculated values that reflects the extremes of all measured values.

PW

Picowatt - Thank you for pointing out my error - Quite correct, the Unit is Amps and not Watts.

I agree, any machine is only as accurate as it is designed to be and poorly designed devices will have much less Precision.

Auto Ranging is a good feature and it does limit, by automatically using the best Conversion Factor, for the value read! EG: 0.001 Volt will be automatically converted to 1 millivolt as we both know.

The DMM can still measure with accuracy however, the discussed issues are not by any means limiting the accuracy of the DMM! At least within the tolerances of the DMM...

I bet, if Agilent Technologies heard the Argument:

... therefore the second digit past the decimal point is meaningless garbage data.

We would still hear the laughing into next year! Just look at all those Zeros!!!

By the way, this is only the bits that the device is capable of, 4, 8, 16, 32, 64, 128, 256, 512, 748, 1024, 2048, 4096... Most of which were never used in these devices as a mask. Many of the IC's onboard read the data, say Voltage as a Bit, then mathematically determining the value read.

For example Voltage range of 0-10V - We have a 1024 Bit Processor, then 1 Volt will be 102.4 - You get the basic Idea...

As Ayeaye Pointed out, it is the analog to digital converter that reads a Value and converts this into a value in Bits, mathematically the value read is converted into its desired Precision: in our above example, if we read 102.4 then we have 1 Volt.

Equally, if we read 103.79 we have 1.01357421875 Volts - Mathematically!

Of course there are many designs and all may vary some but the basic principals are the same across the board in most devices.

   Chris Sykes
       hyiq.org

P.S: I agree Ayeaye - The Device/Design is the problem only by Design. Accuracy/Precision is there, it can be expensive though as you say.

[tinman]

Picowatt - Thank you for pointing out my error - Quite correct, the Unit is Amps and not Watts.

I agree, any machine is only as accurate as it is designed to be and poorly designed devices will have much less Precision.

Auto Ranging is a good feature and it does limit, by automatically using the best Conversion Factor, for the value read! EG: 0.001 Volt will be automatically converted to 1 millivolt as we both know.

The DMM can still measure with accuracy however, the discussed issues are not by any means limiting the accuracy of the DMM! At least within the tolerances of the DMM...

I bet, if Agilent Technologies heard the Argument:

We would still hear the laughing into next year! Just look at all those Zeros!!!

By the way, this is only the bits that the device is capable of, 4, 8, 16, 32, 64, 128, 256, 512, 748, 1024, 2048, 4096... Most of which were never used in these devices as a mask. Many of the IC's onboard read the data, say Voltage as a Bit, then mathematically determining the value read.

For example Voltage range of 0-10V - We have a 1024 Bit Processor, then 1 Volt will be 102.4 - You get the basic Idea...

As Ayeaye Pointed out, it is the analog to digital converter that reads a Value and converts this into a value in Bits, mathematically the value read is converted into its desired Precision: in our above example, if we read 102.4 then we have 1 Volt.

Equally, if we read 103.79 we have 1.01357421875 Volts - Mathematically!

Of course there are many designs and all may vary some but the basic principals are the same across the board in most devices.

   Chris Sykes
       hyiq.org

P.S: I agree Ayeaye - The Device/Design is the problem only by Design. Accuracy/Precision is there, it can be expensive though as you say.

Hey EMJ'
How about posting some test results on your latest setup--would be good to see how it's coming along your end.


Brad

[EMJunkie]

I am not an expert here and many will know more about this than me. I feel it is important to show in the current context however.

See Below attached Pictures:

In this simple circuit, overly simplified possibly, we can see that the Volt Meter Probes are labeled Voltmeter + and - Respectively. A Voltage divider is used, this gives us a Range, in this case 0 - 10 Volts, the same as in out previous example.

For a given Range, if we measure 50 Volts, we can see there is an over load and the Voltage Divider is insufficient for this range. We get 25 Volts on the Analog Pin!

Our Analog Pin might be 5 Volt compatible, or some might be 3.3 Volts, so some circuit protection would be incorporated to protect the Pin on the Chip.

If you want to study this in a bit more detail, I suggest visiting: DIY wattmeter with an Arduino

   Chris Sykes
       hyiq.org

@Brad - I will share some more data soon if things keep going good.