Partnered Output Coils - Free Energy

[hyiq]

"One has to also ask-why has Wistiti not taken this further,if the results were that good?."

who say im out of this..?   

I simply have give a try to what Chris have shared. For sure im not the most qualified to speculate about the result and im not here to convince anyone except me. So I will not argue or defend any point or result here...

The best way to see it is by trying it by yourself and im glad you,Tinman, finally jump in.

For me these POC are definitively a major component and merits further investigations.

ps: im pretty sure you can achieve better result with more turn on your POC...

Hey Wistiti - As always you're exactly right!!! We have not given this up at all!!!

@All - Wistiti is my friend, if anyone attacks Wistiti I am coming for you!

All I have ever asked is to be fair and honest, and that's why I will hammer any one that attacks my friends! My Friends are Fair and honest! Shared their findings freely and honestly.

   Chris Sykes
       hyiq.org

[hyiq]

Chris,

You have referenced the Preva device previously and indicated there were unique operating properties to the device as shown in his video, so I decided to replicate using a ferrite core wound with three identical windings and operating at 15KHz.  The schematic is attached below and shows all probe connections for identification in the scope pix also attached below.

Referring first to the "Preva Test w_2x100 Ohm Load", the Math(red) channel indicates the true input power to be 1.183 watts.  CH2(blu) is the voltage across R1 and is seen to be 4.793v rms which calculates to .2297 watts.  CH3(pnk) shows 9.766v rms across R2 which calculates to .9537 watts for a total output of 1.1834 watts for a COP = .999.  Very efficient but I see no evidence of OU here.

Referring next to "Preva Test w_2x100 Ohm Load KCL" we examine the currents in the circuit to see if there is any violation of KCL.  The reference channels R1 and R2 are stored current measurements for loads resistors R1 and R2 respectively.  The Math(red) channel shows the sum of the ref currents R1/R2 while accounting for phase and show the result to be 51.16ma rms.  This is extremely close to the input current shown on CH4 which is 51.38ma.  Therefore, I see no evidence of any violation of KCL with the device when operating with loads.  In fact, it can be shown that KCL is also not violated without any loads connected. 

So, IMO the Preva device is a very efficient transformer which is no small feat, but not OU!

pm

Partzman - "unique operating properties to the device" and an interesting device that one can "learn a lot from" are very different things Partzman.

   1: MrPreva's device is the start to what I am sharing.
   2: When replicated properly, it is easy and simple to see Opposing Currents in the setup and still have an output.
   3: I have actually shown that one of my attempts was, already under unity: 82% - As is at the time of MY Replication.

In L2, Using Ohms law, and also verifying the Phase angle Correction through a Resistance, being Zero Degrees, mentioned above, we can calculate the Power across the Resistance: Power P = Resistance R * Current I² = 2.3 Ohms (2.2 + 0.1) * 0.54700816 Amps = 1.28925 Watts, which means that a Voltage V across the Resistance R is only 1.722 Volts, verified on the scope, but on the other side of the Inductor, there is 12,54 Volts present.

In L2, Power across the Resistance: Power P = Resistance R * Current I² = 2.3 Ohms (2.2 + 0.1) * 0.23164969 Amps = 0.53279 Watts, which means that a Voltage V across the Resistance R is only 1.10699 Volts, verified on the scope, but on the other side of the Inductor, there is 12,54 Volts present.

So, the huge gains seen above, across each branch L1 and L2, are not Gains across the Resistance, the load. What is going on here, why are we seeing this Gain, but not in our Load? If the input is 2.2 Watts, and Loaded Output is 1.28925 Watts + 0.53279 Watts, we only see 82% efficiency across our Resistive Loads.

Why do we see what we do? Why do we have such a large Voltage Drop across the Inductor? Between 10.818 and 11.43301 Volts...

   Chris Sykes
       hyiq.org

Look, to be blunt, I do get a little tired of doing so much leg work for people, but here, please make an effort to read: http://overunity.com/15395/partnered-output-coils-free-energy/msg489891/#msg489891

All the surrounding context is important to read.

Note: If I say Important, I more often mean there is value in the Knowledge Gained! Any conclusions drawn up after the fact are up to the mind of the individual.


   Chris Sykes
       hyiq.org




P.S: Question - What would you do next, to try to improve this already good result?

[hyiq]

Mmm-ok 

First results are in for the below setup.
This was a quickly wound transformer-so not very neat,and only low power applied,by way of my SG. The loads are two identical !grain of wheat! incandescent bulbs.

Unlike Wistiti's setup,i did not join the two output coil's,but rather placed a resistive load on each coil separately.

EDIT-i forgot to mention--to achieve these results,i had to use a square wave,and a frequency of 12.2KHz.

Still looking for the error,but here are the results so far-measured with both DMMs and scope using a CVR.
The scope and DMMs had only a 2% difference with value's,so an average was taken from the both results.All DMMs were swapped around,and came within +/- 1%
Tried using the clamp on meter,but currents are to small to register.

P/in-6.8vRMS @ 19mA=129.2mW
P/out 1-1.8vRMS @ 41mA=73.8mW
P/out 2-1.83vRMS @ 42mA=76.8mW

So seems to be running at 116% efficiency.

We are close to being within error range with such small currents,but none the less,all care was taken when making the measurements.

I will report back when i find the error-which seems to be oddly elusive ATM.


Brad

Sorry for the quick crappy diagram,but have lots to do ATM.
Also added a pic of the toroid,and as you can see-very crappy winding job.

Hi Brad - When a Cup is half empty, it is also half full! It is merely a point of view as to weather one prefers to view this situation from the Empty or a Full perceptive.

We shall see how this pans out. So far a good result, thank you for sharing honestly and fairly!

   Chris Sykes
       hyiq.org


P.S:   -    3-5:1 / 1:3-5 Turns Ratio is about where this seems to work best. What's your approx. ratio?

[partzman]

[snip]

   Chris Sykes
       hyiq.org




P.S: Question - What would you do next, to try to improve this already good result?

Chris,

With the unusual high efficiency seen in my Preva test, I decided to try some variations which actually showed a slight gain and it was then I decided to question my results.  So, I used 1% 1 ohm non-inductive current sense resistors in place of the current probe and the efficiency then dropped to ~92% range which I place more confidence in than the current probe results. 

Other than that, I don't have any thots on improvements at this time.

pm

[hyiq]

Chris,

With the unusual high efficiency seen in my Preva test, I decided to try some variations which actually showed a slight gain and it was then I decided to question my results.  So, I used 1% 1 ohm non-inductive current sense resistors in place of the current probe and the efficiency then dropped to ~92% range which I place more confidence in than the current probe results. 

Other than that, I don't have any thots on improvements at this time.

pm

Hi Partzman - Forgive me, your scope shots and diagrams are excellent, but I do have trouble interpreting sometimes.

Let me verify, you have verified the two currents in L2 and L3 Coils to be Opposing? Meaning that the Magnetic Fields of L2 and L3 Oppose also?

   Chris Sykes
       hyiq.org