Overunity.com Archives is Temporarily on Read Mode Only!



Free Energy will change the World - Free Energy will stop Climate Change - Free Energy will give us hope
and we will not surrender until free energy will be enabled all over the world, to power planes, cars, ships and trains.
Free energy will help the poor to become independent of needing expensive fuels.
So all in all Free energy will bring far more peace to the world than any other invention has already brought to the world.
Those beautiful words were written by Stefan Hartmann/Owner/Admin at overunity.com
Unfortunately now, Stefan Hartmann is very ill and He needs our help
Stefan wanted that I have all these massive data to get it back online
even being as ill as Stefan is, he transferred all databases and folders
that without his help, this Forum Archives would have never been published here
so, please, as the Webmaster and Creator of these Archives, I am asking that you help him
by making a donation on the Paypal Button above.
You can visit us or register at my main site at:
Overunity Machines Forum



Output Coils

Started by nathanj99, March 02, 2015, 07:24:37 AM

Previous topic - Next topic

0 Members and 3 Guests are viewing this topic.

Print
Go Down Pages 1 2 3 4 5 6 7
User actions

MileHigh

#15
March 03, 2015, 02:03:07 PM
Quote from: nathanj99 on March 03, 2015, 11:15:44 AM
wow, I have been reading up about current sources. I think I kind of get it. But if one uses the output combined with a capacitor to power a light bulb rather than charge a battery, what would the voltage source be? or am I simply not understanding it?

Thanks for all the info everyone, its all very interesting .

Forget about the capacitor in your example to keep it simple.  If you have a current source of one ampere, and the filament of the light bulb is 50 ohms, then the current through the light bulb will be one ampere and the voltage across the light bulb will be 50 volts.

Low-Q

#16
March 03, 2015, 03:05:43 PM
Quote from: nathanj99 on March 02, 2015, 04:27:27 PM
Thank you. Now I have a starting point. Im guessing I wont know what voltage I will get until i start experimenting? I need a circuit to change the voltage down to 12v. Any ideas?
What is feeding the coil with alternating magnetism?
Is the alternating magnetic input constant or not?


If you want to transform the output voltage down to 12 V you must know that the coil produce more than 12 V. How do you know that?
The number of windings doesn't determine the output voltage alone.

If the output is greater than 12V you can use a regular transformer to transform it down to 12V.
Just have in mind that rectified 12V AC will give you about 17V DC.


You can use a cheap buck converter to transform 17VDC down to 12VDC. Type "buck converter" in the search field at www.dx.com. Many models to choose from.

Vidar

Jimboot

#17
March 03, 2015, 03:17:57 PM
Quote from: MileHigh on March 03, 2015, 01:56:38 PM
Why have you been doing this test? 


Because I wanted to

MileHigh

#18
March 03, 2015, 03:28:48 PM
Quote from: Jimboot on March 03, 2015, 03:17:57 PM
Because I wanted to

Okay, so you didn't really know why you were doing the test and you were just doing it by rote.

Most people know that you don't put your multimeter on current measurement and then connect the probes across a voltage source because that can blow the multimeter.

By the same token, you don't put your multimeter on voltage measurement and then connect the probes in series with a current source (a discharging inductor) because that can blow the multimeter.

Jimboot

#19
March 03, 2015, 04:29:46 PM
Quote from: MileHigh on March 03, 2015, 03:28:48 PM
Okay, so you didn't really know why you were doing the test and you were just doing it by rote.

Most people know that you don't put your multimeter on current measurement and then connect the probes across a voltage source because that can blow the multimeter.


You're funny
Print
Go Up Pages 1 2 3 4 5 6 7
User actions