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Overunity Machines Forum



Measuring Amps on output coils

Started by nathanj99, March 16, 2015, 06:16:33 PM

Previous topic - Next topic

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verpies

Quote from: MileHigh on March 22, 2015, 03:39:20 PM
If I recall correctly there is no magnetic field inside a superconductor. 
Leaving aside "flux pinning" inside type II superconductors, that concept gets a little murky when a superconducting ring is considered.  Does the hole in a superconducting ring constitute an "inside" or "outside" ?

verpies

Quote from: tinman on March 23, 2015, 12:18:30 AM
And once this field is poled into the super cooled material , you believe a current is now flowing through that material?-without a voltage potential?
Yes and I find it very annoying when people try to apply voltage and EMF concepts to shorted coils - this is not necessary because coils are inherently current devices (while capacitors are voltage devices, btw). 

Yes, you can do it, as long as a coil has some resistance, that keeps dissipating coil's energy (that's what Faraday's law is about) but it is like fitting a square peg into a round hole with shorted superconducting coils...

tinman

Quote from: verpies on March 24, 2015, 10:47:59 AM
Yes and I find it very annoying when people try to apply voltage and EMF concepts to shorted coils - this is not necessary because coils are inherently current devices (while capacitors are voltage devices, btw). 

Yes, you can do it, as long as a coil has some resistance, that keeps dissipating coil's energy (that's what Faraday's law is about) but it is like fitting a square peg into a round hole with shorted superconducting coils...
Although you believe a coil is a current device,the current/voltage value is dependant on resistance. The higher the resistance,the lower the current,and higher the voltage-disregarding the super conductor of course. The same applies to capacitors. Capacitors can deliver extreem currents across low resistive loads,while the voltage across that load may be low.

Now,what is the difference between a super conducting ring(that has only an internal magnetic field once a current is sent through it,and the good old room temperature PMH ?

verpies

Quote from: tinman on March 24, 2015, 05:17:17 PM
Although you believe a coil is a current device,the current/voltage value is dependant on resistance.
An ideal inductor has no resistance.  Working in terms of voltage with inductors is only needed to account for their imperfections -  resistive "energy leaks".

Also, a natural state for an inductor is when it is shorted and a natural state for a capacitor is when it is opened. 
With ideal components, there is no energy leakage out of them then.

When you do something unnatural for them, e.g. open an energized coil or short an energized capacitor, then all hell breaks loose.

Quote from: tinman on March 24, 2015, 05:17:17 PM
Now,what is the difference between a super conducting ring (that has only an internal magnetic field once a current is sent through it) and the good old room temperature PMH ?
Do you mean this by "PMH" ?

tinman

Quote from: verpies on March 24, 2015, 08:07:47 PM
An ideal inductor has no resistance.  Working in terms of voltage with inductors is only needed to account for their imperfections -  resistive "energy leaks".

Also, a natural state for an inductor is when it is shorted and a natural state for a capacitor is when it is opened. 
With ideal components, there is no energy leakage out of them then.

When you do something unnatural for them, e.g. open an energized coil or short an energized capacitor, then all hell breaks loose.
Do you mean this by "PMH" ?
Yes-like in the video, although I see laserhacker was a little lost as to why he had to short the coil on the Ecore to get the effect, when the explanation is quite simple.