Overunity motor, part3, all 4 recharging bats reading at 1.400 volts now.

[MileHigh]

Floor:

Sometimes threads change direction, that's life.   Beyond that, are you here to be an "ignorance and stupidity enforcer?"  Are you here to stop people from thinking and debating?  Are you here to be a truth suppressor?

Is somebody paying you to stop people from learning so that they will keep on spending their money on junk?

MileHigh

[tinman]

Floor:

   Beyond that, are you here to be an "ignorance and stupidity enforcer?"  Are you here to stop people from thinking and debating?  Are you here to be a truth suppressor?

Is somebody paying you to stop people from learning so that they will keep on spending their money on junk?

MileHigh

Sometimes threads change direction, that's life.

Indeed MH,one should expect this sort of thing by now here on OU. No harm done,and i think the diversion dose relate some what to the original topic,in that it's really the good old inductive kickback showing it's magic again-in way of deceptive voltage climb's of charging batteries-->the hollow charge as i call it.Been caught a few times myself in the !way back when!.

But there is some truth to the !!unused energy return to the source!! The simple circuit i posted a couple of post ago dose exactly this. L1 go's high when L2 go's low,and the capacitive coupling between base/collector junction provides the current path,and keeps the oscillations going-no need for inductive coupling between L1&L2

[MarkE]

There needs be no inductive coupling in order for a JT like circuit to work well. The switching can be done with one inductor and the transistor itself-->no need for inductive coupling between the two inductors at all. You can also return the unused portion of current back to the source-->after it has passed through an LED and another !charge battery.

Here is a simple little circuit i called the cool joule-->works a treat.

Guess what?  I disagree with your claim that L1 is not coupled to L2. L1 shorts the base of the transistor to the emitter.  Absent induced current in L1, as the circuit is drawn there is no source of energy to turn on the transistor.

If you want to try and prove the claim that the circuit works without coupling between L1 and L2, then move L1 a foot away from L2 and connect L1 to the transistor through a pair of tightly twisted wires.  Then, leaving L1 still connected through the twisted pair, move L1 back to the position you have previously had it.

Possible Results:

Circuit works with L1 near or far:  The transistor is receiving bias current from something other than L2 coupling to L1.
Circuit only works with L1 near:  L2 is coupling to L1.
Circuit only works with L1 far:  There is some other energy source int he room coupling into L1.
Circuit doesn't work at all.  Check circuit.

[tinman]

Possible Results:

Circuit works with L1 near or far:  The transistor is receiving bias current from something other than L2 coupling to L1.

Guess what?  I disagree with your claim that L1 is not coupled to L2. L1 shorts the base of the transistor to the emitter.

Many many replications MarkE

If you want to try and prove the claim that the circuit works without coupling between L1 and L2, then move L1 a foot away from L2 and connect L1 to the transistor through a pair of tightly twisted wires.  Then, leaving L1 still connected through the twisted pair, move L1 back to the position you have previously had it.

Been there-done that-->many times.

Absent induced current in L1, as the circuit is drawn there is no source of energy to turn on the transistor.

Incorrect. But dont stress to much Mark-> it had the best of them trying to work it out for weeks.

Circuit only works with L1 near:  L2 is coupling to L1.

Incorrect

Circuit only works with L1 far:  There is some other energy source int he room coupling into L1.

Incorrect

Circuit doesn't work at all.  Check circuit.

Incorrect-Circuit diagram is correct. L1 is not inductively coupled to L2. Tested at distances of 10 meters apart,and in solid steel faraday cages.L1 can be swaped out for a small ceramic inductor,and still opperates.

Lets see if you can work out how Mark,as it took some very talented people some time to do so. In fact,i dont think a conclusion was ever reached
Whats your guess,and we'll see how close you get.

[tinman]

@ MarkE
Hint
Have you heard of the Miller effect capacitance ?