AC voltage from single magnetic pole

[partzman]

https://youtu.be/HrAWejpez38?t=867
this concept will not work but in therms of  measurement I agree.
look below:
Wesley

Wesley,

I don't grasp what points you are trying to make here.  If you don't agree with Arie DeGues on this patent that's fine.

Your issue with the AM503/A6302 combo I don't follow. Obviously this combo does not have as high a frequency capability as the Caddock CSR and Tek TPP0500B probe even when de-skewed properly which was done before these tests were run.

Look closely and compare the blue and green traces which are the CSR and current probe respectively and you will see that the blue trace has a slightly larger current lead than the green.  This is evident from the Math measurements which show the average negative instantaneous product of CH1(yel)*CH2(blu) to be higher than CH1(yel)*CH4(grn).  It is a shame that I didn't measure and display the current lead for CH2(blu) which would show a slightly higher value.

Regards,
Pm

[partzman]

Verpies,

I see that Itsu ran your preferred bicycle test and the conclusion came out with no phase shift.  However, If I understood you correctly (which I may not of), you said the induction source was not important.  If so, how do you explain the experiment I ran in post #133 with a follow up in post #139?  This experiment used a common induction source balanced between the two secondaries and there is obvious phase shift as per Nix's claim!

I lost sleep over this trying to understand!

Regards,
Pm

[stivep]

Wesley,

I don't grasp what points you are trying to make here.  If you don't agree with Arie DeGues on this patent that's fine.

Your issue with the AM503/A6302 combo I don't follow. Obviously this combo does not have as high a frequency capability as the Caddock CSR and Tek TPP0500B probe even when de-skewed properly which was done before these tests were run.

Look closely and compare the blue and green traces which are the CSR and current probe respectively and you will see that the blue trace has a slightly larger current lead than the green.  This is evident from the Math measurements which show the average negative instantaneous product of CH1(yel)*CH2(blu) to be higher than CH1(yel)*CH4(grn).  It is a shame that I didn't measure and display the current lead for CH2(blu) which would show a slightly higher value.

Regards,
Pm

Most often made mistakes :
https://youtu.be/uDcfevfwyoc?t=307
https://www.youtube.com/watch?v=DMXiD3dKYJc
but there is also another  problem with  phase difference.
In this video  it is shown that  (~only)  at this particular frequency 200MHz  using  different probes it makes signal  between two ports of the oscilloscope  inverted  at 180 degrees.
Lecroy: DDE-3000 series. ( in  video)
I have personally:
Lecroy  WaveRunner64xI
https://youtu.be/HrAWejpez38?t=815

The deskew for the current probe and amplifier has been adjusted and calibrated against the voltage measured across Rs with the CH3 probe.

- Yes you can point  at bandwidth limitation but it's not always a case.
So the amplifiers and  probes must be at its best exactly the same and calibrated for an average oscilloscope.
or you get an error in your measurement  and that leads you to  wrong conclusions.



Wesley

[citfta]

Verpies,

I see that Itsu ran your preferred bicycle test and the conclusion came out with no phase shift.  However, If I understood you correctly (which I may not of), you said the induction source was not important.  If so, how do you explain the experiment I ran in post #133 with a follow up in post #139?  This experiment used a common induction source balanced between the two secondaries and there is obvious phase shift as per Nix's claim!

I lost sleep over this trying to understand!

Regards,
Pm

Hi guys.


First a big thanks to both Pm and Itsu for their tests.


Pm,  I see Verpies hasn't answered you yet so if you don't mind I will take a shot at answering your question.  I hope Verpies will soon answer and make any corrections needed to my answer.  I think the difference in your test and Itsu's is the way you are measuring the current.  By using a second coil to measure the current you are essentially measuring the secondary of a transformer.  And of course the secondary is a reactive component.  And any generating coil or power source will exhibit the voltage leading the current in an inductive reactive circuit.  And also exhibit the current leading the voltage if the the circuit is a capacitive reactive circuit.


Hopefully Verpies will explain that better than I have.


Respectfully,
Carroll

[ramset]

Just a note
I believe Verpies has traveled for a
Previous Commitment.


And internet access and time to participate
Are NiL


A return Sometime on Monday