Chas Campbell free power motor

[rMuD]

Chas is a genius,
but I just did a quick calculation and
it can only work,
if the distance of the right side is at least more than 3 times farther away from the axis,
then the left side ( look at his scheme on the wall)...

He always has 6 balls at the left that have to be lifted
versus 2 balls that are on the right side.

So if the distance is only twice at the right side, then you have:
6 x 1 is bigger than 2 x 2 =   6 > 4 , so you see, it would only work if:

6 x 1 is less than 2 x 4  = 6 < 8,
so you see, I guess Chas has not yet the right distance on the right side to make it work.

But the principle is really so simple amazing, that normal people, who
are not playing with it, do not find this !!!

Genius !
Will now upload to overunity.com

Many thanks to Chas and the Ashtweth team !

one problem, as you pass 2x the size on the outer wheel, your angluar distance decreases, and at 3x the distance you only have 1.5x balls on average pushing down

[tinu]

Thanks, Stefan!

Before reaching the 3 digits code, there is a redirect to a page http://www.megaupload.com/toolbar/? containing something like ?All download slots assigned to your country are currently in use.

Hmm,
then your browser seems to be setup wrongly,
I only get this advertisement windows in a new
popup window, which I can close !
Use the Firefox browser and it will work for you...

Srry. It?s not working.
I?m using Firefox and IE. Both behave exactly the same.

Tinu

[hartiberlin]

Chas is a genius,
but I just did a quick calculation and
it can only work,
if the distance of the right side is at least more than 3 times farther away from the axis,
then the left side ( look at his scheme on the wall)...

He always has 6 balls at the left that have to be lifted
versus 2 balls that are on the right side.

So if the distance is only twice at the right side, then you have:
6 x 1 is bigger than 2 x 2 =   6 > 4 , so you see, it would only work if:

6 x 1 is less than 2 x 4  = 6 < 8,
so you see, I guess Chas has not yet the right distance on the right side to make it work.

But the principle is really so simple amazing, that normal people, who
are not playing with it, do not find this !!!

Genius !
Will now upload to overunity.com

Many thanks to Chas and the Ashtweth team !

one problem, as you pass 2x the size on the outer wheel, your angluar distance decreases, and at 3x the distance you only have 1.5x balls on average pushing down

how do you mean this exaxtly ?

My upper conclusion was also wrong, because I did not count in the angles...

I have drawn down now the diagram of the wheel on paper and taking the
5-0-10 dimensions, that means 2:1 distances that Chas uses,
it gets clear, that at the
left side only 5 balls count for the leverage and at the right side
only 2 balls count in.

Putting in the angles we got then on the left side for the 5 balls:

2 x 0.5 = 1
2 x 0.9 = 1.8
1 x 1    = 1
=========
sum: 3.8 units

Now on the right side we have:

1 x 1.8 at about 2 o?clock= 1.8
1 x 2 at 3 o?clock = 2
====================
sum: 3.8

So this would not get us a running wheel,
this is why we need a bigger distance.
This will be calculated in the next message.

[rMuD]

my calculations were off..   less than 23% of the time will 2 balls be on the down stroke at 3x sized outer wheel




if anyone wants the orginal visio file, just let me know..   base radius of each circle is 2 times the orginal   to be exact  2" 4" 6" is size  the 39 degrees is a theoretical maximum, no slope was provided for the ramps, where the 4" outer wheel has slopes calculated in, maximum at 0 degree slope is 60 degrees

[Humbugger]

Chas is a genius,
but I just did a quick calculation and
it can only work,
if the distance of the right side is at least more than 3 times farther away from the axis,
then the left side ( look at his scheme on the wall)...

He always has 6 balls at the left that have to be lifted
versus 2 balls that are on the right side.

So if the distance is only twice at the right side, then you have:
6 x 1 is bigger than 2 x 2 =   6 > 4 , so you see, it would only work if:

6 x 1 is less than 2 x 4  = 6 < 8,
so you see, I guess Chas has not yet the right distance on the right side to make it work.

But the principle is really so simple amazing, that normal people, who
are not playing with it, do not find this !!!

Genius !
Will now upload to overunity.com

Many thanks to Chas and the Ashtweth team !

one problem, as you pass 2x the size on the outer wheel, your angluar distance decreases, and at 3x the distance you only have 1.5x balls on average pushing down

I believe that between these two posts, Harti's and rMuD's, we have the whole problem neatly placed in a nutshell.  Unfortunately for all those whose hopes are sky high, the convergence on why this wheel will never spin on its own is very rapid if you consider these two posts carefully and objectively.

I have drawn up a super-simple diagram in Autocad which shows me the obvious fact that as the ratio of the two diameters is increased from two to three, what rMud says is exactly true or even worse.  There are only two balls on the right side for a very few degrees of rotation. 

At all other times, only one ball can be on the right side, as the lower ball has been delivered to the lower return ramp and yet there is significant rotation that must take place before a new ball socket comes into position to receive the next ball from the upper ramp. 

I'm smart enough to see all of this clearly, but too dumb as yet to figure out how to upload an Autocad drawing here.  I'll try though...give me a few days for editing...

http://www.overunity.com/index.php/topic,2487.msg48099.html#msg48099

At a ratio of 3.8637 to 1, the linear supply and return ramps reach the theoretical limit of having no possible slope left to deliver balls left and right, since the linear vertical chord distance between positions on.the outer wheel is exactly one unit, same as the inner wheel diameter.  At this ratio, the maximum number of balls on the right side at any given moment becomes one.

In the words of the entirely mortal Mr. Mercury...Another One Bites the Dust.  Sorry!

Humbugger

EDIT:  I was off busily drawing my little picture and trying to figure out how to upload it while rMuD beat me to the punch!  Nice work rMud!  I'll have to get Visio!  You and Harti share the debunking prize on this one. 

Congratulations!  Saved a lot of folks a lot of time they can apply to other ideas and pursuits hopefully.