Thane Heins Perepiteia.

[broli]

OU  ......   without any reference to input power to the motor driving the system  ??

To be OU, your 21 watts electrical output and shaft torque (mechanical output) combined must be greater than the input power consumed by the driving motor.

Without input power data versus output power (including shaft torque measurements) data, your claim of "WE ARE OPERATING AT OVERUNITY" is extremely tenuous.

Cheers

Both if you may have valid arguments. It depends on how efficiently the motor conserves the electric energy to mechanical at 25rpm.

[CRANKYpants]

OU  ......   without any reference to input power to the motor driving the system  ??

To be OU, your 21 watts electrical output and shaft torque (mechanical output) combined must be greater than the input power consumed by the driving motor.

Cheers

OK, THE MOTOR AND GENERATOR ARE BOTH 100% EFFICIENT AND ALL THE ELECTRICAL POWER IS CONVERTED INTO MECHANICAL POWER IN THE DRIVE SHAFT AND THEN ELECTRICAL POWER IN THE GENERATOR (WE USE MAGNETIC BEARINGS IN A VACUUM).

WITHOUT THE HV COILS ENGAGED THE MOTOR CONSUMES 0.003 WATTS TO PRODUCE 0.003 WATTS, EFFICIENCY = 100%

WITH THE HV COILS ENGAGED THE SYSTEM ACCELERATES AND THE FIXED MOTOR INPUT = 0.003 WATTS (ACTUALLY IT IS GENERALLY ABOUT 50% LESS WITH HV ACCELERATION BUT FORGET THAT PART) AND THE GENERATOR OUTPUT = 21 WATTS.

21/0.003 x 100 = EFFICIENCY 700,000%

CHEERS
T

[broli]

OK, THE MOTOR AND GENERATOR ARE BOTH 100% EFFICIENT AND ALL THE ELECTRICAL POWER IS CONVERTED INTO MECHANICAL POWER IN THE DRIVE SHAFT AND THEN ELECTRICAL POWER IN THE GENERATOR (WE USE MAGNETIC BEARINGS IN A VACUUM).

WITHOUT THE HV COILS ENGAGED THE MOTOR CONSUMES 0.003 WATTS TO PRODUCE 0.003 WATTS, EFFICIENCY = 100%

WITH THE HV COILS ENGAGED THE SYSTEM ACCELERATES AND THE FIXED MOTOR INPUT = 0.003 WATTS (ACTUALLY IT IS GENERALLY ABOUT 50% LESS WITH HV ACCELERATION BUT FORGET THAT PART) AND THE GENERATOR OUTPUT = 21 WATTS.

21/0.003 x 100 = EFFICIENCY 700,000%

CHEERS
T

1 million % would have been rounder. I think you'd pass that if you did divide by 2 AND considered the kinetic energy of the rotor.

[CRANKYpants]

hi,

This is my new test with 0.2mm coil wire

http://www.youtube.com/watch?v=1JC0UwnZrcU

Lenz's law working.

VERY NICE VIDEO! 

LENZ NAMED HIS LAW AFTER HIS WIFE - WHO WAS A PERSISTENT BITCH! 

MAY I SUGGEST 100 OHMS OF 30 GAUGE WIRE ON AN AC MIG WELDING ROD?

CHEERS
Thane

[CRANKYpants]

1 million % would have been rounder. I think you'd pass that if you did divide by 2 AND considered the kinetic energy of the rotor.

WELL OF COURSE I WANTED TO BE CONSERVATIVE AND NOT RUFFLE ANY FEATHERS... 

kinetic energy of the rotor

NO KIDDING A 10 LB ROTOR ACCELERATING UP TO 3500 RPM FROM 25 RPM WITHOUT ANY ADDITIONAL POWER TO THE MOTOR - WHILE DELIVERING POWER TO A LOAD AT THE SAME TIME - BOTH - GOING UP AND COMING DOWN.

T