Stubblefield coils (bifilar) and speculations

[mthompson]

@mthompson
If I connect cu10 and fe6 with the meter, I will short out the wires just as if I connectec 5,6. BUT I think what you are saying is that if I connect 10 to 6, I will not be nullifying the magnetic field, while I am creating the voltage etc.

Lets say the copper wire is (-) and the iron wire is (+). The coil is standing so its core is vertical, up and down. The two ends of the iron and copper coils where you started winding are at the top, and the other two ends where the coils terminate are at the bottom. The winding was done so if an electron moves from the top to the bottom it passes downward in a counter-clockwise motion, whereas if it passes upward it is moving in a clockwise motion. Lets say we are looking at the movement of the electrons and not the conventional fiction of electrical flow as the movement of + charges.

If you make a connection between the ends at the top then the electrons will, more or less, move up the length of the copper wire coil in a clockwise motion to the connection with the iron wire and then proceed to move down its length in a counter-clockwise motion - the circuit is completed by the electrolytic movement of ions between the two wires along their length. The flow in the copper wire (clockwise) is the opposite of the flow in the iron wire (counter-clockwise) and their magnetic fields will be correspondingly opposite as well. One will probably predominate so there might be some magnetism exhibited by the core but not much.

If you instead make a connection between the end of the copper wire at the top with the end of the iron wire at the bottom the electrons will basically flow up the length of the copper coil in a clockwise motion, then down thru the straight shunt, and back up the length of the iron coil again with a clockwise motion. The flow in each coil is in the same direction (up and clockwise), and their magnetic fields are merged and reinforced. The slight magnetic field from the current flowing down in the straight shunt is not significant.

The part about not nullifying the magnetic field is mysterious, because when the wires are wound down then back 3 complete times, the field should be nullified by doing nothing else.

No, because what is important is if the current is flowing clockwise or counter-clockwise. Up and down doesn't mean much as long as the movement around the core stays the same.

[jeanna]

mthompson,
Have you made one of these?
It is a little hard to follow these thoughts because they seem to be opposite what we see.

the copper is +
the iron is -

Stubblefield's drawing shows the winding as seen from the top to be clockwise.

Also winding back the direction looking from the top remains the same, but since it is now being wound upwards, would that make it counterclockwise? and therefore turn the electron flow??

Lets say the copper wire is (-) and the iron wire is (+). The coil is standing so its core is vertical, up and down. The two ends of the iron and copper coils where you started winding are at the top, and the other two ends where the coils terminate are at the bottom.

The winding was done so if an electron moves from the top to the bottom it passes downward in a counter-clockwise motion, whereas if it passes upward it is moving in a clockwise motion. Lets say we are looking at the movement of the electrons and not the conventional fiction of electrical flow as the movement of + charges.
The flow in each coil is in the same direction (up and clockwise), and their magnetic fields are merged and reinforced.


No, because what is important is if the current is flowing clockwise or counter-clockwise. Up and down doesn't mean much as long as the movement around the core stays the same.

maybe now some of this will get clear??
I hope

thank you for doing this

jeanna

[storre]

@mthompson

I made a drawing to visualize the flow better. I think you are right that you need to connect the reed switch to the correct end of the bifiler.

In this drawing lets say the red wire is copper and the black is iron. In the left example the fields would cancel each other out as the reed switches pulses on and off but in the second example they fields would be turning in the same direction and would create a magnetic field until the field increased enough to open the switch which would turn off the field and then the switch would go to it's naturally closed position and the cycle would start over again. How fast the field saturates enough to open the relay would determine the frequency and I think that would be determined by the amount of turns.

So if this is matched up with the NS patent then the reed switch would go on 10 and 5 or 10 and 6, making sure one side of the reed switch is the copper wire and the other side is the iron.

[jeanna]

I think I just thought of a clearer way to say this.

Lets say we start at the beginning of the winds at terminals 10. wind down then back it is all clockwise as seen from the top.

But

on those same wires wound the same way,

start at the ends called 5,6 and you will be following a counterclockwise direction throuout the layers until you arrive at the innermost wires and their ends called 10

Now it can start all over again.

thank you

jeanna

[jeanna]

So, if it doesn't matter whether the winds are going up or down, then I think you have explained something crucial.

The first pulse will make a polarity of one direction,

when the pulse ends (at the 5,6 terminals) and turns around, the polarity will go the other way.

Now what is the reason nothing should be on the terminals 10 and the switcher going off n on is at the 5,6?

Shouldn't there also be a switch at the terminals 10?

thank you,

jeanna